Point Slope Form Archives | Every Step Calculus

Point Slope Form Calculator

February 16, 2019 by Tommy Leave a Comment

:: Video Transcript ::

Hello again, Tom from Every Step Calculus, Every Step Physics dot com. A point slope form calculator, that’s what we’re doing here. This calculator when you buy my programs and load them into you titanium here. It’s really my notes from many tests I got from all over the country. And when I find out a problem, I want to take the notes. Well, you take the notes you put them, great notes, and you put how to do the problem ok right? Then you always have it, that’s what my calculator does ok? Index(8) to get to my menu. Oh, by the way, there is a little square to the right of your screen here of this video, if you click on that you can subscribe to my channel and get more videos to you and you can see more videos. If you do that for me I certainly appreciate it. Index(8) to get to my menu you load that into the home screen of the calculator. And then we’re going to scroll to, I’m going to go with the curser up because it goes to the last, bottom of the alphabet work pumping, oil. And then we’re going to just just click up here to, to the P section and look for a point-slope equation. See R’s. There’s point-slope equation. Click on that when it says busy here it’s loading the program. Question of a tangent line, here’s where we learn y equals MX plus B that’s what we learned in algebra right? It’s the point-slope form equation. I always give you the equations because in a test you’re you’re scored by partial credit in the class curve so whatever you can throw down in your test paper even the equation is give you two points, and you’re looking for the most points okay? To get a good grade and get get out of there so now I gave you the choice here’s the two points right? So we’re gonna choose number one scroll to it or choose number one. We’re gonna enter the points we have to press alpha first, alpha five alpha 7, alpha six, alpha 8, now we show you what you’ve entered, you can change it if you want. I say it’s okay, and let’s do it the slope M is the slope with y1 minus y2 divided by x1 minus x2 pretty simple yeah, if you learned that and study it and remember it pay attention I guess you can remember this stuff. So here’s the y1 which is 7 and then 8 and divided by, divided by 5 minus 6 then equals minus 1 divided by minus 1 equals 1 that’s the slope. Now slope just as a kind of an information thing that’s this is slope is what the first derivative gives you okay now if they gave you a 1 here notice there’s a 1 over 1 and you have rise over run so to graph this slope. When you do the derivative of it you’re gonna go up 1 on the y-axis and 1 over on the x-axis and draw a line from that point down through the origin of the graph and that’s the slope that you’ve just figured when you do a derivative so keep that in mind okay? And then we’re gonna find the line crosses y-axis so we’re gonna take y1 equals M x1 7 minus 1 5 7 minus 5 equals 2. Equation of a line is y equals MX plus B equals 1 X plus 2 that’s C now if you graph that which I will show you right now that’s what you found okay? That’s the line that goes through that point okay? Let’s do a new, let’s do the other problem here here’s number two a point and the slope they got the point and the slope here okay? So let’s do that one number two alpha – 2, alpha 3 and to the slope alpha – one. I know it is there say it’s okay we could have changed it if we made a mistake and here’s the calculations plus three you can go slow here and learn it if you want to learn it but best things to buy my program just do it. And here’s y equals MX plus one now let’s look at that slope. That’s the other direction almost hits the origin of the graph but not quite okay? So anyways pretty neat huh everystepcalculus.com go to my site buy my programs and pass calculus plus I’ll give you the all the help you need you can call me and if you send me tests I’ll make sure it does the test for you but your practice tests or whatever I’m your private tutor here that it will help you all I can I’m interested in in fooling that professor and getting out of calculus that’s my goal that was my goal when I program these in the first place and I got A’s in calculus okay so I’m a genius at calculus now that’s for sure after 25 years so buy my program that enjoy passing calculus, hey have a good one!

Point Slope Form: The relation to calculus

March 14, 2012 by Tommy 1 Comment

The equation of a line to a point on a curve (point slope form) includes the slope and the position of that line on that curve function. It’s better than the derivative because the derivative only tells us the slope. Again in Algebra the professor forgot to tell us the importance of that and the relationship to the derivative. Didn’t make it interesting enough to sink in and how it relates to the real world.

You have a function. Has to have x^2 in it to be a curve from my understanding, Example y or f(x) = 3x^2

Graph that and you have some form of curve in this case a “valley” parabola, (my own word), -3x^2 and you have a “mountain” parabola (again my own word).

Pick any point “(x,y)” Example: (3,12)

Point = (3,12)

x = 3

y = 12

Find the derivative: f(x) = 3x^2

f’(x) = (2)(3)x^(2-1)

= 6x^(1)

= 6x

Compute the derivative at the point “x”

f’(3) = 6(3)

= 18 = m = slope

Point slope form = y = mx + b

y = 12 so:

12 = mx + b

m = 18

12 = 18x + b

x = 3 so:

12 = 18(3) + b

= 54 + b

b = 12 – 54

= – 42

y = mx + b

= 18x + -42

If you graph this equation along with the original function you’ll see the tangent line to that point on the curve

The slope = 18/1 (rise over run)

The angle of that tangent line = tan^(-1)(18/1) = 86.8 degrees

(make sure your calculator mode is in APPROXIMATE and DEGREES)

Fabulous and exciting, right? lol Tom

p.s. You’ll love my programs

Have a test or quiz on point slope form? Here is a video example using the programs on the TI-89 calculator: (Click Links below)

Point Slope Form Calculator

Point Slope Form Given Two Points

First day of calculus I

March 14, 2012 by Tommy 2 Comments

In my first day of calculus I – the chalk was flying. That professor started with the fundamental theorem of calculus, probably said “if it exists” a hundred times, and never let up from then on. It got worse from then on and never better. I, with others – I’m sure – sat there in disbelief and in a fog. I was 50 years old that day. I remember 3 semesters later I turn to the guy next to me and ask, “What the hell is a derivative?” He whispers, “I think it’s an angle of a line or something”.

Try it yourself go up to any one of your friends, ask them first if they’ve taken calculus and then ask them what a derivative is, and see what the say or don’t say. That’s the way all of my professors taught in my experience of college, I never enjoyed one class. If it was me – and my inability to learn in a class – that kid would have told me what a derivative was without any question as well as others in the class, however nobody knew (I asked several others after that kid) they didn’t know either. We were all three semesters into calculus and didn’t know what a derivative was. What the hell is that? Isn’t knowing what a derivative is, in no uncertain terms, more important than the fundamental theorem of calculus???