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You are here: Home / U Substitution / U Substitution Integral x^2/(x^3+1)^2 | TI-89 Video

U Substitution Integral x^2/(x^3+1)^2 | TI-89 Video

October 16, 2013 by Tommy Leave a Comment

 

U-Substitution Integral on the TI-89: Raw Transcript

This video is on u substitution uhm with regard to calculus
for your tests and homework and let’s get started
you have to press second alpha first to put the letters i n d e x in here
then press alpha and put the eight and the open and closed parenthesis
press enter and you’re into my menu I’m already at u substitution
but you can see there’s many many things in here
for you to pass your calculus tests and do your homework
I was never really interested in learning this stuff
I just wanted to know how to do it for my tests and homework
ah, but were going to do u substitution that’s the way my programs are designed
all of my programs including my physics programs
uhm u substituion lets put the
you have to press alpha before you put anything in the entry lines
here in my programs
so I press alpha and let’s put in x squared divided by the
quantity one plus x cubed to the second power
I always show you what you’ve entered so you can change it in case you’ve made a
mistake I say it’s ok
we’re going to evaluate x squared divided by x cubed plus one over two
and we rewrite the program to put the x squared over by the dx here
and of course there’s one in the numerator there
and we choose, i tell you what to choose to isolate the x you take the three and move it to the other
side for the du du divided by three equals x squared dx
and then we of course change the function to u
1 over u squared same thing as one over what you entered there
and you do the calculations notice that we have du divided by three
but you always take a constant or fraction and move it to the front of the integral sign
here which I’ve done for you
and then you have you have to change u two to the numerator
you can’t integrate with a division or times sign
you have to change it to a single numerator and so we have u to the minus two
and you add one to that which becomes a minus one
and you get one third over one to the minus u
and etcetera and here’s your answer uhm pretty neat huh
every step calculus dot come go to my site
buy my programs and pass your calculus

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