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Calculus Solver Software | Solve Calculus Problems | App

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Ok this is a video on a calculus solver for calculus problems, my programs are
perfect for solving all kinds of solving calculus questions and problems. The are
designed for tests really, I’m not interested that you learn it or that you memorize
it, I am interested that you learn enough to pass tests and get out of calculus
somehow. That’s what my programs were designed for me to do, and hopefully
for you if you purchase them. Anyways let’s get started – you press second
alpha to put the I n d e x in the calculator, then you push alpha eight and closed
parenthesis to get to my menu, then you press enter and up comes my menu.
You can scroll down for many, many different things. I have graphing by hand, ya
know, concavity and vectors where you can put in a and b vectors. Here’s cos of
a and b which is two vectors, and you find the angle of it. Definite integral,
Definition of derivative, which is pretty interesting. Equations of lines, integrate,
gradient, graphing by hand, implicit differentiation, Inflection point, graphing by
hand, limits, line integral, log – p and q points – P and Q points is interesting
because that’s in calculus three really, because they give you the end points and
these vectors show direction, where the other vectors show just, they are really
called scalars, but this is actually a directional vector, when you get p and q
points, x y and z variables. Well let’s do p and q points here to see what
happens. Wait for it to load here, and you’re going to put the – you’ll notice your
going to have to put the x value in, you’re going to have to press alpha and put
eight, that’s what they’ll give you in test, and then you are doing the y value, and
so your going to put alpha minus nine, and then alpha, I don’t know maybe put
four in here. An then we’re going to do the q point of the vector, again alpha,
let’s go minus five, alpha minus eight, and alpha ten. I show you the points, what
you’ve entered, see if you want them right, you look at your test to see if you’ve
entered them correct, and then if they’re correct, we press ok, and we can do all
kinds of these different things, sphere equation, we can do sphere radius, we
can scroll down to sphere radius – sphere remember is calculus three because
we’re into spheres, which are three dimensional things. Here we have the mid
point, we can go mid point here. Center of a sphere is a mid point and it’s given
by pq, I give you the formulas, and here we have four minus eighteen over two,
and then calculates to that vector. Standard equation, press five, these are all
standard equations – center point, press two, center of a sphere is the midpoint
and is given by pq, there’s the center again, we already did that. Radius, there’s
radius, it’s a square root and then squares within the square root, approximately
seven point eighteen units. So make sure that when you look for a calculus
solver, that you are looking at my programs, because on the Titanium there is no
better solver for calculus than what my programs do, people have said that over
and over again. Every step calculus dot com, check it out.

 

What Calculus Professors don’t tell you about e^(x)

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One of the toughest things to do in calculus is to recognize or recall what to do with a given problem in order to solve it. Professors tell you about the problem their trying to teach but they don’t tell you about the subtle differences, what to do if this happens or is changed.I was programming – integrating e^(x) problems on the Titanium or TI-92+, or Voyage 200, for you folks using integration by parts and was really proud of myself – the step by step answers for most problems were coming up using the formula u*v – ∫(v*du) — all of sudden there were wrong answers compared with what the calculator was coming up with using its integral program or system.  Why??  So here’s what I find, and have written another program to handle it. Remember I don’t program to learn or teach calculus – I program to pass the pathetic tests, to pass the class, and get hell out of there, never to touch the subject again. So:Anything with e^(x) or e^(ax)   (“a” being some arbitrary number) even when connected to sin(x) or tan(x) or ln(x) etc is an integration by parts problem.

However:

Integrating anything with e^(x^2), e^(3x^2), e^(3x-1), e^(5x+6) is U- substitution.

To make it clear — if there is an exponent within the exponent of e, or if there is a minus sign or plus sign within the exponent of e you are using U- substitution.

Now isn’t that fun!!   What professor told you about that in class.  When I program this stuff  – I (and the program) have to know those differences, the program has  to work line by line, step by step with the best system possible to solve the problem logically and correctly. Enjoy my programs!

Arc Length Tutorial on the TI-89

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This is a program on arc length, and let’s get started. To get my code in here to get my menu to come up, you have to put the letters i n d e x, which you do by pressing 2nd alpha, on the Titanium first for the letters and then alpha and you can enter the eight and closed parenthesis on there, press the enter button and you are into my menu. Here’s all the choices goes way down here, you can find all kinds of things on here which will help you out in your test, your homework, or just leaning about it, because its so perfect step by step, and it’s all what we wished we could have when we were looking on how to do a problem. That’s why I did it for myself first and now am offering it to you. Let’s do arc length, were going to press the number four here and get into the parametric form which is the r t form with time and radius, and three variables x y and z in this one. And this one is the Cartesian system which is equal to y = f of x, either one will give you the function there. And so we’re going to press two and enter a function. Press alpha and let’s put the function in here, we’re going to go, x cubed divided by six plus one divided by parenthesis two times x, closed parenthesis and over the range of – we have to add alpha again to get the range in here – we’re going to do it, one half to the upper range of two. It shows you what you’ve added here so you can correct it if it’s wrong or check it out here. I say it’s ok so we’re going to press one – derivative of the function here, with respect to x is x squared over two, minus one over two x squared. Here’s the formula for the arc length, the integral over the range of a and b, the square root of one plus dy dx squared, and with the respect of x. Here we have the function into the formula here, this is the part that was squared, here’s what we did the dy dx part, which we found before, mark all of this on your paper of course. Here we’ve taken the square of that, still have the square root to do, one plus, but we’re going to take the square first, like you would in normally doing a problem, here we added the one to it, here we’re going to do the square root of it, which is this. Working the formula through, here’s the, as we integrate it, here’s what the integration is over the range of two and minus one half. We put the two in the problem, two to the four minus three over six times two, which I show you here, equals thirteen twelve’s and we put the one half in here, we subtract the lower from the upper, and we added the half into the formula, here’s minus forty-seven forty-eight. And we can see that we had a minus forty seven, this will trip you up a lot of times, where there’s a minus to a minus, I do it to make sure it doesn’t happen to me, when I’m doing the problem. Thirteen twelve’s plus forty seven forty eight, the answer is thirteen sixteenths, approximately two point zero six two five, rounded to the fifth place. So pretty neat huh, everystepcalculus dot com, check out my other fabulous programs, you’ll love them, worth every penny that you buy it for, so cheap compared to the thousands of hours I’ve spent on this stuff studying it for you, to make sure they are correct and everything, and remember it encompasses calculus two and three and one, so you are buying all three semesters of your calculus in one purchase, ahh have a good one.

Calculus Video – Inflection Point – Graphing on the TI89 Titanium app

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Ok, this graph is on inflection points, or inflection point of a graph, and let’s get started – you put index8 in here, ya know, second alpha for the letters and then Alpha eight, closed parenthesis, and that’s the code for my menu to come up, and here’s the menu, of all different things that I’ve programmed so far, so we want inflection point – so we’re going to scroll down here, there all in alphabetical order, so were going to scroll down to inflection point there – press enter – and you can see that this is graphing by hand, you have concavity, critical points, crosses the x and y axis, inflection point, intervals of increase and decrease, and local maximum and mins. All these come up in my graphing by hand program that I have designed. And so, I tell you to, ya know, mark of course on your graph paper or test this, ya know graphing, ah axis, and then we’re going to enter the function, so – you have to press alpha first – let’s enter minus x cubed plus three times x squared minus two, press enter twice, it shows you what you’ve entered – you can go back and change it if you want, I say it’s ok and I’m going to press number one, and you can get all these from that function, you can get all of these uhm different answers, so we want inflection point number six, I’m going to press number six and uhm, notice the way you do the inflection point, you take the first derivative and then you take the second derivative, here’s the six times x times x squared the first derivative and then the second is six minus six times x, and then we’re going to factor it, factor the second derivative and you get minus six times x minus one equals zero, so x equals one – x component of inflection point – and you plug that into the original function – I show you how to do that here – here’s y – the original function – and we’re going to put one in for x – here’s x cubed plus and plus one into three x squared, and when you compute that out it comes to zero – so the inflection point is really one and zero – x equals one and y equals zero – mark this on your pencil graph and label it, ya know, pretty neat huh, check my web site out – everystepcalculus.com.

Concavity Graphing on the Calculus App TI-89 Titanium Video Example

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okay this the US and concavity with respect you sketching graphs by hand and calculus and ago go over the concavity test and put in a concave function you know or a function so we can check cavity check concave up concave down and so let’s get started you have to press 2nd L for to get into my menu and then you have to add I and the X you know for the letters and then you press alpha and then you put in the number eight and then they close parentheses left and great pride to seize any press ENTER and we’re into the menu he were interested in kind cavities are we gonna go to number eight your press number eight and here we have the different different things that we can do with the function as we enter the function so I always tell people to start a graph paper star in your you know because this is a test and you’re gonna put your graph in your city mark these different points on the graph as you go enter the function its that senator here alpha have to enter alpha before you enter anything here X cue -6 times X where plus guy times X us to shows you what we’ve entered you can say okay or change it I say it’s okay and then we’re gonna choose never to kind cavity oppressed number two but were in the concavity sure you definitions have concave up or down you notice that this is a maximum point appears so that we’re going to have a concave down and if this is a minimum point you have concave up Harry involved in the second derivative so we find the second review function XQ minus X 6x squared last night experts to and we find our first first X where tax equals which is actually critical point or inflection point I’m sorry inflection point the x value you can find inflection point it’s another part of the program so with every we have to have a number greater than to inflection point to see where this concave upward our handwritten into the second derivative 6 times three -12 when we come up with six and that’s positive so concave up and then we’re gonna get a number less than the inflection point FX less than 2 choose one and the second really plugged in the second derivative market stuff on your paper going don’t leave anything out or as everything’s partial credit and calculus so anything you mark down correctly you get credit for it and this because it’s a negative sexy was a concave down so I should be there from Infinity 22  its concave down years inflection exploit and above that to to infinity is concave up for any every step calculus that come check out my site check out my program you love them

Calculus -Vectors – Program App – TI-89 Titanium Calculator

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This is a video on vectors, and let’s get started here. You have to press second alpha to get to the letters of my menu code, i n d e x and then press alpha again and put in the eight and the closed parenthesis, and press enter and you are into my program, you’ll notice you can scroll down to get to the a b c’s of the beginning of it a and b vectors but you know that’s also goes to vectors but we can go, scroll down in case you want to call it just plain vectors, and we’re going to press enter and get into the vectors program. Press alpha before you put anything in here, were going to press alpha eight, alpha minus twelve, alpha nine, for vector b, the x y z coordinates, we’re going to put in alpha seven, alpha minus thirteen, and alpha minus fifteen, I tell you what you’ve entered so you can change it if you want, I say it’s ok, I’m going to press number one and we’re into all the different functions, if you want to find the magnitude of vector B, press three, and do the calculations, shows you what your doing here and you get absolutely do all the calculations, square root et cetera. We can go a plus b, number 6, a plus b, eight twelve, et cetera, come up with the a plus b answer. We can have a plus b plus c it’ll, three vectors find their resultant and components. We have to enter the vector c, alpha eight, alpha six, alpha minus two and again check whether we’re doing it, vectors a b and c , resultant, b minus a et cetera, let’s do the cosine, cosine between a and b, that’s the formula there, you write all this stuff on your paper of course, and we’re doing the dot product of it and then we’re doing the rest of the calculations, does all of the calculations for you, and gives you in radians or degrees. Pretty neat huh? Everystepcalculus dot com. Check out my site and purchase the programs if you want, and enjoy my programs.

Parametric Equations, Calculus Program, App, TI 89 Titanium

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This video is on parametric equations. A parametric equation is, you’re adding a
parameter of t time to every x y and z function, and that’s where we add the
parameter and that’s the reason we call them parametric equations. And let’s do
it. Turn the calculator on here. We’re going to get back to the home screen here.
Clear the calculator we can go F1 eight and it clears that screen here. You press
second alpha and put in the letters i n d e x, and then you push alpha and get
into the number 8 and closed parenthesis to add this and get my formula for my
menu. Press enter and we’re into my menu. And you can see all the things
available in my menu for you to pass calculus and do your homework. Position
vectors, product rule, projection of a and b, all those kinds of things you will be
involved with in calculus one two or three. We’re going to do parametric
equations now. That’s concerned with position vectors. If z is not given you
enter zero in for z, then you can do the other two, x and y. So there’s the vector
r t is generally an r t, is equal to this vector here, x t, y t and z t. So you have to
press alpha to enter the functions in the entry lines here, so let’s do it, three
times t let’s say plus four for x t, here’s y t, let’s enter have to push alpha, five
times t and let’s do the z one, or let’s put alpha just for to make it simple and put
z you can see that the z one is zero. Gives you a chance to change it if you’ve
made a mistake, and we have all these things that we can do with this formula
now with these functions in there. We can eliminate the parameter. Which
eliminates the t and changes it back to an x function. Let’s do that quick, I’ll go
through these quick so you can see. You solve for t, here’s the solution for t, and
then you substitute t into every other x y and z, but ah here’s one point six seven
times x minus three point nine and that eliminated the t parameter. Let’s go
length of arc, you want to do that, fine, let’s go press four, notice it’s an integral
over a and b, with the derivative of the r t formula. And rt we’re going to put in
what we entered, I’ll go through it quick, put this all on your paper, write it down
exactly as you see it, and we’re doing the square of each one, over the time of
let’s say, you have to push alpha, let’s say from two to alpha six, shows you from
two to six, here we’re doing this, write this on your paper and each individual one
is gone, there it is, and here we substitute etcetera in there, and here we have
approximately twenty three point four units. We can do speed, do you wanna do
speed, let’s push number seven here and do speed, unit vectors or speed is the
square root of these squared. Square root of nine, twenty five zero. 5.8 meters
per second. Ah pretty neat huh? Everystepcalculus dot com, check it out. Go to
my site and you’ll love these programs.

 

Cross Product Example

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This video is on cross product. Many people have asked for it and I’m going to do it in my fabulous programs. Press 2nd alpha, to get the letters, enter index, 2nd alpha again and 8 (). So you should have, index 8 () to get to my menu. Go to cross product, press enter. It has for vector A and you press alpha to put anything in the empty lines in all my programs. This is the way the calculator operates. Then we’re gonna press alpha 8, press enter twice, input alpha -6 enter twice, alpha 4 and enter twice. These are for the vector A. For vector B, enter alpha 4, press enter twice, alpha -8 remember the negative sign is different from the minus sign for equations. Enter the y component of the B vector alpha -9 enter twice, z is alpha 4 enter twice. This is what we’ve entered: A = <8., -6., 4.> B = <-8., -9., 4.> Select ok (or change if you want) Now up comes the menu for all vectors and those things we’ll be able to do it. Here we have cross products, A x B cross product which is different from B x A cross product. I do both of them for me and you. Gonna do A x B first. Here are the vectors: A x B (cross product) =
= < 8., -6., 4.,>
X <-8., -9., 4>
Matrix multiplication
= <8., -6., 4.>
<-8., -9., 4.>
Press enter and see the calculations for i,k,j vectors or coordinates
=[(-6.) (4.) – (4.) (-9.)] i –
[(8.) (4.) – (4.) (-8.)] j +
[(8.) (-9.) – (6.) (-8.)] k
Enter and it keeps doing the multiplications
= [(-24.) – (-36.)] i –
[(32.) – (-32.)] j +
[(-72.) – (48.)] k
= 12i – 64j 120k (i,j,k system)
= (vector notation)
Now B x A cross product and here are the calculations
=[(-9.) (4.) –
(4.) (-6.)] i –
[(-8.) (4.) –
(4.) (8.)] j +
[(-8.) (-6.) –
(-9.) (8.)] k
Down on the page, do them all perfect
=[9-36.) – (-24.)] i –
[(-32.) – (32.)] j +
[(48.) – (-72.)] k
= -12.i + 64. J + 120. K
= <-12., 64., 120.>

Pretty neat, everystepcalculus.com, buy my programs you’ll be thrilled.

Implicit Differentiation

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This video is on implicit differentiation, let’s get started, you press second alpha
to put the letters in my code here to get to my menu, and then you press alpha again
to get to the eight and the enclosed parenthesis. Then you press enter and up comes my menu I’m already at the implicit differentiation one but you can scroll, ya know, up to what
ever you need here. If you are after this subject then that’s what you do. You press
enter to get into my program. I give you an example of it. You can use that here. You
have to press alpha first to put anything into that line on the Titanium, So were going
to do alpha y cubed plus y squared minus five times y minus x squared, press the equal sign
and minus four, you have to use the minus to the left of the enter button, not the one
the take away minus sign. And then you see what you’ve entered, check whether it’s
correct or not, if it is you press ok. And here’s the system, you differentiate both
sides with respect to x, the left side and the right side of the equation, which we did
here, and the answer is minus two x equals zero. You can see minus two x is the derivative
of minus two x squared. This is all partial differentiation, which you get in calculus
two mainly. And with respect to whatever, even though there are y’s, z’s or x’s
when you differentiate with respect to x, you just find the derivative of the x variables
in that function, and leave the others alone. That’s what we’ve done here. And then
you take the x here and move it to the right side of the equal sign, that’s algebra of
course. And then you are going to take the derivative of the left side with respect to
y, and this is the answer three y squared plus two y minus 5, which is the first derivative
of all these indications up here. And then the answer is dy dx . You take the right side
and divide it by the left side and here’s the answer. I give you the option to evaluate
it at a point. Sometimes a problem will ask you to do that. So we can do that now, you
have to press alpha and we can put in seven, and then maybe alpha minus six, and here’s
the x y point. Check if it’s right, if it’s wrong you can change it otherwise were going
to say it’s ok, and notice that the seven goes into the x’s and the minus six goes
into the y’s. You put that down on your paper, and here is the answer two over thirteen,
which is the slope of the line, rise over run. Notice that if you take two increments
up the y axis and over thirteen on the x axis and draw a line from that point down through
the center zero zero,. That’s the slope of that line. However it’s not a tangent
line. A tangent line is touching the point that you indicated, or asked to evaluate things
at, and I tell you that here just to remind you. And of course if you want to get that
you have to use the y equals m x plus b equation, which is in my programs also, I’ll show
you here. Go back to the main menu, number three. You press three and go back to the
main menu, and you can see that here is the equation of a tangent line, and that will
set that line right on that point. If you graphed it. Pretty neat huh, everystepcalculus.com,
check out this program and other programs.

Arc Length

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Arc Length in Calculus with the TI-89: Raw Transcript

This is a program on arc length, and let’s get started. To get my code in here to get
my menu to come up, you have to put the letters i n d e x, which you do by pressing 2nd alpha, on the Titanium first for the letters and then alpha and you can enter the eight and
closed parenthesis on there, press the enter button and you are into my menu. Here’s
all the choices goes way down here, you can find all kinds of things on here which will
help you out in your test, your homework, or just leaning about it, because its so perfect
step by step, and it’s all what we wished we could have when we were looking on how
to do a problem. That’s why I did it for myself first and now am offering it to you.
Let’s do arc length, were going to press the number four here and get into the parametric
form which is the r t form with time and radius, and three variables x y and z in this one.
And this one is the Cartesian system which is equal to y = f of x, either one will give
you the function there. And so we’re going to press two and enter a function. Press alpha
and let’s put the function in here, we’re going to go, x cubed divided by six plus one
divided by parenthesis two times x, closed parenthesis and over the range of – we have
to add alpha again to get the range in here – we’re going to do it, one half to the
upper range of two. It shows you what you’ve added here so you can correct it if it’s
wrong or check it out here. I say it’s ok so we’re going to press one – derivative
of the function here, with respect to x is x squared over two, minus one over two x squared.
Here’s the formula for the arc length, the integral over the range of a and b, the square
root of one plus dy dx squared, and with the respect of x. Here we have the function into
the formula here, this is the part that was squared, here’s what we did the dy dx part,
which we found before, mark all of this on your paper of course. Here we’ve taken the
square of that, still have the square root to do, one plus, but we’re going to take
the square first, like you would in normally doing a problem, here we added the one to
it, here we’re going to do the square root of it, which is this. Working the formula
through, here’s the, as we integrate it, here’s what the integration is over the
range of two and minus one half. We put the two in the problem, two to the four minus
three over six times two, which I show you here, equals thirteen twelve’s and we put
the one half in here, we subtract the lower from the upper, and we added the half into
the formula, here’s minus forty-seven forty-eight. And we can see that we had a minus forty seven, this will trip you up a lot of times, where there’s a minus to a minus, I do it to make
sure it doesn’t happen to me, when I’m doing the problem. Thirteen twelve’s plus
forty seven forty eight, the answer is thirteen sixteenths, approximately two point zero six
two five, rounded to the fifth place. So pretty neat huh, everystepcalculus dot com, check
out my other fabulous programs, you’ll love them, worth every penny that you buy it for,
so cheap compared to the thousands of hours I’ve spent on this stuff studying it for
you, to make sure they are correct and everything, and remember it encompasses calculus two and three and one, so you are buying all three semesters of your calculus in one purchase, ahh have a good one.

Integrals

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Raw Transcript

This video is going to be on integrals, rewriting an integral, and also evaluating one. Lets get started – you have to press second alpha to put the letters of this code in – you just do this once and up comes the menu for you – and you push alpha and then eight and closed parenthesis, and then press enter, and up comes my menu of all the items – I know that what I want to go to is the letter p, they go from numbers here, but then they go p, so you can scroll down like this, all the way down – or if you know what your after you can go alpha and then p, and I’ll go to – I want to rewrite the integrand first – so I’m gonna – one of the most important parts – I tell you one of the most important parts in here – and so
you kinda go to this list here – and these are the tough ones – so you go to your list and like for instance let’s do number six here – press number six – n over x squared – you need to convert the denominator always to a numerator, and that in algebra becomes x to the minus two, n times x to the minus two, and then you integrate – you’re going to go integration of n to the x to the minus two – which you can do it now, and here you have – n to – notice you add one to the exponent up here and then all this you divide by that also – minus two plus one – that equals n to the minus 1 – minus one. So that equals minus n over x – and you can go to another one here, lets try number 5, here’s the cube root – well cube root of course is exponent of, to the one third, and to integrate x to the one third, you have to add one, well one in one third is three thirds, so you add that and divide, and put that in the denominator also, and you have x to the four thirds over four thirds, and when you divide by a fraction you invert and multiply, and so here’s the answer, three x to the four thirds, over four. Ahh pretty neat huh, well I wanna do, I’m going to go here and quit, lets scroll down here – and we can quit on either end of it – press enter – now if you wanna, I’m gonna go alpha and p again to get back to the program, I’m gonna – I want to evaluate, I’m gonna press number two, and evaluate – and for demonstration let’s just do uhm – you have to press alpha before you enter anything in this line here – alpha, and let’s go uhm – t times uhm – sometimes they use the variable t – times – let’s use e to the x here, e to the x of three times, t squared. And it shows you what you’ve entered here – I show you – and you can go ok or change it – I’m going to say it’s ok, so – and I don’t do it step by step particularly – uh – because this is u substitution – uhm – but anyways – ah – this is the exact answer. And so that will help you immensely – ya know – checking your integrals with any type of integral – quickly – and the step by step I have in other sections of my programs like for instance u substitution – so – fabulous programs, check em out at everystepcalculus dot com

Quadratic Equation

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Transcript

Ok, this video is on the Quadratic formula, lets get started. Again we press
second and then alpha to enter letters and then my menu. Code is I n d e x
and then alpha eight and then closed parenthesis, then press enter. From here
you – You can scroll up if you want to go to the bottom of the menu – they are
all alphabetical – the menu items. And there we have the quadratic formula
there. First of all, I give you a little information on what it is, and why we use it.
Then I give you the formula, which you write on your paper – the first thing you
do, and now we’re going to add a, b, c of the variables. So let’s do alpha minus
sixteen, press the enter twice, and then you have to go alpha maybe seven, and
then alpha let’s try three. Shows what you entered so you can change it if you
want. I say it’s ok. And then after that, if you want the quick answer you scroll
to this one or press the number in front, one or two, or step by step. Let’s do
the quick answer right now, I’ll press one, shows what you write on your paper
there as you’re adding the variables, and then this is the exact answer and this is
the approximate answer. Exact answer for x, a minus point two six six and point
seven o four. Press enter and you can go back to the main menu, or you can
quit, or you can do a new quad problem. Let’s do another, ahh, let’s go alpha
minus eight , and nine, and alpha two. Now you’ll notice this didn’t get nine so
we need to change it. So I’ll press number two and go back and enter it again.
Let’s go alpha minus eight, alpha nine, and alpha seven, that’s better, say it’s
ok. I want the step by step answer this time, so we go through it and you write
everything you see on your paper here. And you can see here is the exact again
and here is the approximate answer for one x, and here is – you are doing minus
or plus ya know on this part of the discriminate, and here is the exact answer or
the approximate answer. Pretty neat huh? Everystepcalculus.com. Enjoy my
programs.

Vectors Video

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Raw Transcript

Hey this is tom the calculus and physics guy who programs the TI89 calculators and other calculators for the TI system. uh… today or this video I’m going to be talking about or showing you how how fabulous my programs work on the vectors my site is EveryStepCalculus.com and enjoy my program this is two vectors in space uh… starting from the origin to x_y_z_ uh… points you notice we start again from the index 8 and in the home screen to get to my programs and up comes a menu with all these different types of things that you can compute and we want to do the vectors today so we’re gonna do a-b and vectors we add the first one is it asking for the x_y_z_ point of the first vector uh… vector a again and x_y_z_ and alpha 8 alpha minus seven alpha minus three vector b alpha sixalpha minus five alpha seven shows us what we have if that’s correct and you can go here and press oknow you notice they have the magnitude of vector a choose that one and you can see where the magnitude comes to eleven units uh… shows you how to do it eight squared you know square root of 8 squared minus seven squared minus three squared go back vector B same thing press the this shows you how to do that part uh… a minus b all these different vector calculations come up i wanted to do them when i was in college quickly and not waste time with it and get them exactly accurate vector a minus b is 2 minus b minus 10 if you want to find the magnitude of a minus b you can go a minus b and find that the shows you how to do exactly that putting in the variables dot product and then well move on here got all these different choices A cross product…length B times a cross product B times A there’s a difference uh… constants against a times b times a area of a parallelogram component of A in direction of B equation of a plane all these things cross product is pretty cool ’cause that’s a matrix system and shows you there and then does all the calculations for you and there’s the in the cartesian system i j k system or the vector system with the arrows on the ends of it uh… pretty neat huh enjoy my programs at EveryStepCalculus.com.

Limits Calculus

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Limits in Calculus on the TI-89: Raw Transcript

This is a video on limits as it applies to calculus, generally calculus one, and let’s
get started. You have to press second alpha to get to my menu. You can scroll down from the menu many things you want, all in alphabetical order, we’re going to go down to limits and press enter. Here’s the choices in the limit program you have with regards to limits. You can compute the limit, see the definition of a limit formula, complete a table of limits, and prove that a limit is equal to the computed limit. You can also find delta given epsilon. We’re going to do the first choice now finding delta given epsilon. You have to press alpha before you enter anything in the boxes that come up in my programs. We’re going to try two times x minus five equals one as x approaches three and the epsilon they give you, They will give you these things on the test problem they give you, so epsilon equals point zero one. So I show you what you’ve entered. The limit of two times x minus five equals one, as x approaches 3, while epsilon equals point zero one. The next screen you have the choice of changing it or saying that it is ok. I say it’s ok so I’ll press one for the choice. Here’s the first formula, absolute f of x minus L is less than epsilon. I took the one over here and added it to the minus five to get minus six equals zero. That’s an absolute value sign not a one, and that all is less than point zero one. You’ll keep writing this stuff down on your paper exactly
as it shows. This is the way it done on youtube videos, or at least what I could find, and
delta equals point zero zero fine. Now we can go back to choose main menu or new problem, we want to do a new problem so I’ll choose one again and then go to number two and compute the limit. You can put anything in you want within reason. Alpha again, anytime you are doing division you have to put parenthesis in — in any problem — so we want to make sure we get the parenthesis in there. Let’s go parentheses x minus two closed parentheses, divided by, parenthesis x squared minus x minus two, closed parenthesis. As x goes to alpha two. Here’s the problem you’ve entered and you want to compute the limit. You say it’s ok. Now at x equals two, f of x equals zero and therefore doesn’t exist, so you use the following to find the limit. You add point zero one to every x in the formula so you are a very little away from the limit given and then compute it. The limit is point three, I give you other ways of showing that, because some tests require other answer forms.
Let’s do another problem, let’s do a table of limits — number four — let’s clear
that out and do another one. Alpha closed parenthesis x minus closed parenthesis divided
by x squared minus four, as x approaches two, and here’s the table you’d mark down on
your paper. Let’s do another problem, this is always fun. Prove that the limit is L — the limit
— this is done in always calculus one and throws every student off. Youre panicked because
they are talking about epsilon and delta and the definition of it, which sounds quite complicated, and of course it is useless for the rest of calculus in your life. Let’s put a problem in here. Alpha three times x plus five equals thirty-five as x approaches ten, You have to press alpha again to enter the ten. and here’s what your problem is. Here’s the
formula again. F of x minus L is less than epsilon. You write this stuff down exactly
as shown on your paper. You factor it and then x minus ten is less than epsilon divided
by three. Epsilon becomes delta, and here’s the proof. If zero is less that absolute x
minus c — c is a constant — and is less that delta, then zero is less that absolute
x minus 10 is less than epsilon over three and therefore the original function is less
than epsilon. Put this on your paper and get one hundred percent on that problem. EveryStepCalculus.com check it out and check out the blogs also.

Difference Quotient

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Raw Transcript

Hello, this is Tom from everystepcalculus.com. I’m gonna do the difference quotient for you today or what others call the definition of a derivative. We’re gonna get started. Turn calculator on, press 2nd Alpha and put index the alpha again, then 8, then () and press enter. Up comes my program menu, you can see the things I’ve programmed so far. There is a graphing section with the calculus and graphing, maximum and mins among others. But today we’ll be doing a definition of a derivative or difference quotient, which ever you know, either one will take you to the program. Press enter and you are in the actual program. Every time you see pause here, you can enter. We’re gonna put in an example, for instance, (you have to press alpha first when you put anything for these boxes) I like to use 7*^2-7*x. Now you’re gonna substitute for every x in the function, x+h Should look like this: f(x) =7*x^2-7*x select ok or change it if you want. This is the formula, the f ‘ of x = the limit as h goes to 0 h represents the change of x. Formula should be: f’ (x) = lim h->0 = f (x+h)- f (x) h h represents x Jot down on your paper then put in your function. Notice I’ve substituted “x+h” for every function and the original function all divided by h. F’ (x) 7*”x+h”^2-7*”x+h” = -(7*x^2-7*x) h Very complicated program, took me a long time, maybe a month to do this program. Worked a lot with research to do it, calculus books and such. So, you’re gonna write this on your paper, but you’ve taken the x squared of the function and worked it out. F’ (x) 7*x^2+14*h*x+7h^2 “-” (7*(x+h)) -(7*x^2-7*x) h Keep writing these down and eventually you’ll get: F’ (x) = lim h->0 =14*x+7*h-7 @ h=0 Answer = 14*x-7 And you’ve gotten a hundred percent on that problem and you look like you know what you’re doing and everything else. Everystepcalculus.com you can go to a new problem, main menu or you can quit or do what you want. Enjoy my programs.

Video Examples: Trig Functions

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Raw Transcript

This video is on trig identities derivatives and integrals as they apply to trig functions and let’s get started we have um second alpha allows you to put letters into the calculator or the screen I_n_d_e_x alpha 8 closed parentheses, closed parentheses tells you uh… for calculus and up comes a menu and we’re going are you can go up and go down in the last part of the alphabet and we want to go maybe trig and half angle formulas for that pretty interesting program you can scroll down and choose whatever you want for instance lets start something easy like cosine of x and you notice the derivative of cosine of x minus sign of x and the integral of cosine of x is sine of x plus c identities or one over secant cotangent sine of x sine of x over tangent of x double angle formula cosine of x equals sine of two x divided by two sin of x these are all things that come up in calculus and you either memorize them or you know them your a genius or like me would trigger my mind once i get away from sin or cosine and um… was able to add the identity to come back and do some problems lets take for instance the next one cosine squared of x half angle formula his equal to one-plus cosine two x divided by two pythagorean identity is one minus sine squared x derivative you have the original function cosine squared of x which is really cosine of x times cosine of x and so you have the product rule here which we use f prime then would be cosine of x times the derivative of cosine of x plus the derivative cosine of x times cosine of x and it works out to these uh… cosine of x minus sign of x et cetera et-cetera and that’s how they get the derivative of two sine of x cosine of x pretty interesting lets do one more.

Definite Integral

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Definite Integral on the TI-89

Raw Transcript

This video’s going to be on definite integral…where you take the integral of the function and then compute it at a lower and upper parameter and ah, really your finding the volume of something within a certain range and so let’s get started here you have to press second alpha this shows you’re gonna enter letters into the calculator i_n_d_e_x press Alpha again to get back to the number system on the calculator and press here comes my menu all the things you want to do chain rule area a parallelogram okay

e^(2x) Integration by Parts

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e^(2x) Integration by Parts on the TI-89 Series

Raw Transcript

This is a video on integration by parts and doing a integral of e to the x. Some function with e to the x. Get started here, again 2nd alpha so that you can enter the letters of my code to get into my menu index 8( ). Closed parentheses tell the calculator that you want to do a program. You can scroll down to e^(x) integrate, that involves integration by parts. In this program you have In(x) , e^x, sin(x), cos (x) but choose e^(x).
Here is the formula: Evaluate a e^(x)
Integral
=v*u – ∫[v*(du)]dx
Here is an example: 2x*e^(-x) that you can add. So you would know how to put the function in or what function to use or something in that form. It will be on your test, and remember these come from tests so the test that I’ve seen I can do them, the program can do it. It is a certainly difficult subject if you ask me. I’ve programmed it for days and I couldn’t do a problem right now from memory without the help of my calculator. So any time you get a pause, you press enter and go to the next section. You press alpha x* press the blue key and e^ over the x button. You get this system of adding the e to the x like the calculator wants. Add x and closed parentheses. X*e^(x)
And here’s what you’ve entered: ∫[x*e^x]dx that’s for integration.
You can change it if you want otherwise select ok. This will come up
∫[x*e^x]dx
dv= (e^x)dx
v= ∫[e^x]dx
= e^x
u= x
du = (1)dx
You have to choose dv first as dv is the derivative. So we have to integrate that to get up to e. Then we have to get u and the derivative of u. There is a 1 in front of the u, so the derivative of u is 1. In case there was 3x, there would be a 3 there example, du = (3)dx.

Here’s the formula again, here’s what we tried to integrate
∫[x*e^x]dx
= v*u – ∫[v*(du)]dx
= (e^x) [x]
• ∫[(e^x) (1)]dx
= x*e^x
-∫[(e^x)]dx
So then we’re gonna evaluate and here’s the answer
∫[(x*e^x)]dx
= x*e^x
-e^x+c
Remember in tests you’re tested on curves and you get partial credit for anything, if you could put the formula down or anything intelligent you’re gonna get some credit for it. So that’s what my theory was when I was into tests and calculus and to somehow pass the class.
So enjoy my programs, everystepcalculus.com

sin(2x) integration by parts

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Raw Transcript

okay this videos on integration by parts with regards to sin(x) let’s get started 2nd Alpha enter my code for my menu i_n_d_e_x if you watch my other movies your used to this but it’s always good to review. Alpha again 8 and closed parenthesis and again your into my menu we have integration by parts, length of an arc, limits line integral, all in alphabetical order so you can do anything you want here. We’re going to goto integration by parts, with regard to sin(x) I’ll give you an example of what you might want to put in there. We’re going to put in…you have to press Alpha before we put anything in these entry lines here. We’re going to go x times and then we have to go the second to get to the sin function And let’s go 3 times x. And let’s press ENTER twice and it shows you what we have entered we can change it of course, I say it’s okay, and we’re into the equations or into the solving of it. OK, here’s the original function you choose dv. and v is equal to the integral of sin of 3x dx that equals minus cosine 3x divided by 3 and then u is going to be x and then du is going to be 1(dx) here’s the original function again, here’s the formula, v times u minus the integral of v times du dx so we add this, v is equal to minus cosine 3x over 3, and u is equal to x. We have the integral of d, which is minus cosine of 3 of x divided by 3 and times du one and we work it out write this stuff all on your paper as your doing your problem. Exactly as you see it. Here’s your answer equals a minus x cosine 3x divided by 3 plus sin of 3x over 9 plus C. Every Step Calculus dot com, check it out.

 

Quotient Rule Help

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Tom,
Im not getting the right answers on the quotient rule. I plug in the values exactly as shown on the youtube video and for the f prime of x and the g prime of x my calculator is plugging in zero for both of those derivatives. Help would be much appreciated. Thanks-

A newbie to calculus

-Eric

On larger problems there is no way to see the rest of the problem or solution on the Titanium, however my theory was and is — that the programs are used to pass my tests and not to see if they can do harder problems. Large problems never appear on a test because no one would pass it. Smaller problems are tough enough and all I wanted was to not fail the class and get out of there never to see calculus again. I just needed to get a start on a problem with a formula or something or — get the problem exactly correct, showing work, I knew they wouldn’t solve all the test problems, but tests are based on curves and partial credit so I knew I’d score higher than the person next to me with the calculator help. Good luck, let me know if something doesn’t work correct. If you want to I’d appreciate any actual practice test or mid term test or quiz for you to send me so I can keep up to date on problems that are chosen for tests. Thanks,

Tom

ps I’m finishing up a better program the definition of a derivative or sometimes or also called the difference quotient, and I’ll send that to you in a day or so.