U-Substitution Video using Log Rule on TI-89

March 2, 2014 by Tommy Leave a Comment

U-Substitution using Log Rule Video Example

Raw Transcript

Hello everyone I’m Tom from every step calculus dot com.
Im gonna do a U-substitution problem
that requires the log rule. And uh,
let’s get into it. index8() is my,
you have to put that in the end line here to get to my menu.
I’m already at U-substitution.
You scroll down with the cursor to get there.
And wait for it to load here for a second.
And we’re gonna enter our function. You have to press alpha before you enter anything in my
entry lines in my programs.
Alpha 8 times
X divided by
parentheses
X squared plus 1
I will show you what you’ve entered. The reason you need to do a log rule is
notice in the denominator your have x squared plus one.
This is an exponent of 1. If you we’re to
transfer this up to the numerator the exponent of
one would become a -1. And in integration you always add,
the first thing you do is always add to the numerator.
And one plus minus 1 is zero so the answer will always come out to be
-1. That’s the reason anytime you see this without, without an exponent other than
one. The one is of course hidden. Um,
you know it’s a log problem.
So we’re going to press there.
Say its okay. Here’s the original
function. And all these you have to rewrite them. Notice there is a constant error
of 8. You have to bring that outside the integral, that’s very important. And we’re going to also
take the x
here and put it over by the dx.
And we’re going to put one in the numerator,
for X squared plus 1 in the denominator.
So U is x squared plus 1 the derivative of that is 2x.
Another trick to all these, took me a long time to figure out.
Was d you need to have the divisor of 2
You have to move that over as a divisor here, and leaving
this here. You’ll notice that X DX is the same as x dx.
That means it’s a U-substitution problem if it wasn’t it’s not a
U-substitution problem. I ask you that though just
to make sure you know what you’re doing. I say yes.
So we have i8 outside the integral and one over you
du number 2. Now we have a constant here at one half.
So we have to bring that outside the integral, which we do over here.
8 and 1/2 that equals 4.
And then we have four times log of U. Anything over one of U is
log of u, plus c.
And the answer is, after we substitute the u back in.
4 times log of x squared
plus 1 plus c. Pretty neat huh?
Every step calculus dot com. Go to my site buy my programs, pass your calculus
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have these programs for the rest of your life your kids or grandkids or
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you know, so that you can see the future
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February 20, 2014 by Tommy Leave a Comment

Related Rates TI-89: Airplanes in Flight

Raw Transcript

Hello Tom from every step calculus dot com.
Going to do related rates problem. Let’s get started.
index8() in the entry line here to get to my menu.
Press Enter. We need
related rates are we could get average average rate of change.
Both the same.
And we’re gonna do in this problem this is two airplanes passing each other.
At a certain time. And
what’s their rate of change as they separate. And
in these kind of problems we’re gonna, we’re gonna go to north, south, east or west.
In the menu which is number 8.
You can scroll down with the curser or you can press the number before it.
I press number. And
were going to do the problem. The most important part of north and south
is this pathagorum theorem type thing which is,
and then the derivatives of that. Your
implicitly differentiating
both sides of the equation to come up with the most important part. Here’s the
thing if you can figure out
(x) and dx/dt.
(y) and dy/dt and your gonna get
dz/dt which is most the time what they ask for.
Which is the hypotenuse of a right triangle.
So make sure you mark this down on your paper.
Here’s how you got it.
Of course the 2’s are cancelled, I put this here.
They always give you time. So in this,
in this problem they give 9:00 am so we’re gonna press number two to go to a.
And we’re going to push alpha, to push
alpha before you enter anything in these entry lines here.
alpha 9 a.m. and the other one is
a.m. also so I’m going to press to 2 here. And put in alpha
11. I will show you what you’ve
entered, so you can change it if it’s a mistake, 9 AM and 11.
And of course that’s two hours elapsed time
in between this flight here. And we’re going to enter the speed of the
first plane which is
Alpha
0:00
Miles per hour we’re going to choose number 3. And the direction here is East. We’re going
to choose number three again.
And then we have the other plane which is
alpha 180
And that’s going south, we’ll press number 4.
The miles per hour will be the same for both. It will be the same.
So here again I show you’ve entered you can change it if you want.
I say it’s okay. And
the first thing you do is find out X with respect to time.
So about 90 miles per hour.
And about two hours it’s 180 miles per hour.
You write this down on your paper, there’s a system for doing these problems.
on related rates. Then we need to know the hypotenuse
that’s the pathagorum theorem. So we do it here, you write this on your paper
that’s 402 miles per hour, that’s the hypotenuse.
And you plug these factors in X 180 dx/dt
was 90 and here’s 360.
And dy/dt was 180, divided by 402
which is, and this is the formula here.
(x) dx/dt plus y dy/dt
divided by z equals dz/dt which is they’re asking for. So 201
miles per hour. 100 percent on this problem on
your test. EveryStepCalculus.com go to my site buy my program pass your calculus test.
I promise you and also subscribe to me if you wanna see
future videos or blog.

Related Rates: Change in Cube’s Heat & Volume

February 16, 2014 by Tommy Leave a Comment

Related Rates: Change in Cube’s Heat & Volume on TI-89

Raw Transcript

Hello everybody, Tom from EveryStepCalculus.com
I’m gonna do a related rates problem again, um and relationship to a cube.
Remember related rates always have some sort of formula to differentiate on both sides and come up with their answers. And let’s get started. index8()
to go to calculus one menu press ENTER here
you sometimes they call it average rate of change
or related rates in test
you can scroll on that one right I’m going to scroll down to
related rates there’s related rates there
I give you a list of things
keep adding to it in this case we want a cube is heated in the problem that
I’m showing here. And so we’re going to choose that
because it says a cube is heated your going to go to here
and related rates here find the rate of change in the volume
of a cube due to heating and of course here’s the formula
for the volume of a cube sided cubed
s = side and
they give you what the side
is. You have to press Alpha before we enter anything in my entry lines here.
And they give it is 12. Now they might
give you inches, feet, meters or centimeters. In this case they give you centimeters.
So I give you that choice. And then they give you the,
what’s changing with regard to heat. You have to press
Alpha. In this case they get .1. And of course they have seconds, minutes or
hours depending upon what the problem gives you. In this case they give you minutes, I’m going to Press 2.
I always show you what you’ve entered, so you can change it if you want.
Here’s 12 centimeters and .1 centimeters per minute.
I ask if it’s OK.
Here’s the answer 43.2 centimeters cubed per minute.
And, notice that your differentiating the v, volume.
And differentiating the formula
which is side cubed.
And that becomes dv/dt differentiating V.
And then we’re, we add our
derivative.
S cubed is equal to 3 S squared.
dS/dt we’re taking the derivative of
side with respect to time. And here’s three times 12
squared. And then we add the change of
rates. These are pretty easy but why not, even if they are easy, why not do it
with the program. Just so you do it within 10 seconds and be done with the problem
on a test. Then go onto something else. You can memorize it
and do it if you want. This is much better
EveryStepCalculus.com go to my site buy my programs and pass calculus. And
don’t forget to subscribe to me for different videos and blog.

Related Rates | Spheres Radius & Volume | Every Step Calculus

February 11, 2014 by Tommy Leave a Comment

Related Rates | Spheres Radius & Volume Test Question

Related Rates Sphere Radius Question for TI-89

Raw Transcript

Hello everybody this Is
Tom from EveryStepCalculus.com I’m gonna do a related rates
problem right off the internet and this
problem was the first when i searched
related rates for a sphere and related rates is always got some sort of formula
to it they deal with cones and
spheres and cylinders and
this one is a sphere so we’re going to get started index eight to go to my
calculus one menu and we’re gonna
you can go up or down on this, this scroll up there down by like to go up
if the
the letters are r there related rates which is closer it z than a
and wait for it to load here
and you can see this
arrow here and on any menu shows you that there’s more to it than that
they’re all in alphabetical order so sphere would be
in the s section here’s sphere
and in the problem that
was on the youtube your asked to find
dv/dt in other words how much is the volume changing
with the change in radius and so we’re going to choose number two
to do that and the radius rate that they give you
is 4 so we to enter anything into these entry lines on my program any of my
programs you have to press alpha
first alpha 4 and
the problem says its increasing we’re going to choose number two you can scroll to it
here or you can choose a number before it
I like to choose the number it’s quicker and it says per second we’re going to choose
that
and then it gives a diameter
so the radius but the formula is with radius so that needs to be converted
you give you a diameter the little tricks in calculus or physics they love the trick
you
and so the diameter is alpha
he gives an alpha of 80 and which is the radius of 40
divided by 2 and he gives millimeters
notice how many variables there are in this problem in other words millimeters
per second um, the
related rate for the radius and
change in volume so you you got many
things this one he gives millimeters
so we’re going to choose that I show you what you entered so you can change it if you want notice
millimeters cubed per second and the radius is millimeters then
have to be the same I say it’s okay
you write this all on your paper here’s the computation of the actual formula
within related rates in other words we’re taking the derivative
verses with respect to time to
of both sides of the equation there’s
v and here’s the right side and that turns into
4 pie r squared dr/dt then you add the variables here
and what comes up is 25600 pie
millimeters cubed per second now notice that
you would get 100% on this problem but if you had minutes you would have been
wrong if you had feet you’d be wrong et cetera so
the program catches all this stuff so you get a 100%
fabulous program one of the best I’ve written
go to my site
buy my program to pass calculus and if you want you can subscribe to me also
and
see future movies and enjoy my programs as I show them
and also a blog

Related Rates Test: North-South-East-West Rate of Change

February 10, 2014 by Tommy Leave a Comment

Related Rates Test: North-South-East-West Rate of Change on TI-89

Raw Transcript

hello everyone Tom from every step calculus dot com
uh, gonna do a related rates problem
with north and south and east and west type of problems that
occur on tests, and planes going north and going east and
what’s their rate of change etcetera and
we’re gonna do a number 6
in this example put index eight in here to get the calculus one
menu and we’re gonna scroll up to get to the bottom of the menu and get two related
rates
press Enter
and we’re gonna do
north south east or west number 4 here press 4 or you can scroll to it like with
the cursor here
or you can just press the number before
you write this on your paper x
squared plus y squared equals z squared we’re going to do the derivatives of each one
d/dt of x squared plus y squared on this side of the problem
and z on the other side here’s what you get
you get 2x..derivative of x squared is 2x
etcetera derivative
of y squared is 2y respect of t which is time
and same thing with 2z the 2’s go out
you can divide through by 2 and so you get this right here
write all this on your paper just exactly as you see it nothing left out
the only things that
dx/dt is given that means that the x axis
horizontal is what their after
let’s see, a man begins walking
due North so due North is the y so
it wouldn’t be that one, so the woman is walking east
which is on the x axis
so were gonna do alpha always press alpha
before you enter anything in these entry lines here alpha 4
and then the Y
the man is going north so he is going alpha 3
and after time of one hour what’s happening alpha
1, show you what you’ve entered so you can change in case you made a mistake, it’s
okay
write this on your paper x is dx/dt over t is at 4 over 1
your entering all the variables here
x equals 4 y equals three
and then we can do
the pathagoram Theorem all this is easy if you know it but I mean on a test
even if you do know it is nice to do a problem quickly and be done with it
and get 100% on it and move on to something else so Z equals five
so that’s the answer 5 miles per hour
make sure you write all this on your paper
every step calculus dot com
goto my site buy my programs pass your calculus class and also subscribe to me if you
feel like it
for a future blog or movies if you have a
related rates problem you can send it to me and I’ll program it here
right for you

Video for finding dy/dx with the Quotient Rule

February 10, 2014 by Tommy Leave a Comment

Video for finding dy/dx with the Quotient Rule:

Raw Transcript

Hello everyone Tom from EveryStepCalculus.com. I’m going to do a problem that a student asked to be solved. See if my programs could do it. So here it is. index 8 to get to my menu and we scroll to in the menu scroll to log problems and we want to differentiate so we’re going to choose number seven you can scroll or with the cursor, or else choose a number, I like to choose the number before it quicker and number two we want to do a log of base…something. We’re going to enter our function. You have to Press Alpha before you enter anything into these entry lines here, your going to press alpha and then we have to gonna press actually second alpha so we can put in the log which is l o g and then um. alpha to put the 5, for the base and then parentheses. And we’re going to put the square root of x divided by always use parentheses in the denominator 5 minus x, close off the parentheses. I always show you what you’ve entered so you can change in case you made a mistake, say it’s OK. And we have y equals log of this the calculator changes this because it switches around the 5-x to x-5 there’s a log rule applying here dy/dx equals log of a(u) this is the base a and whatever’s in here is the u and here is the formula for the log rule. You write that all in your paper and u is this part of the problem and so we’re going to do dy/dx that’s what it’s asked to find and we’re putting this into the log rule. Now this part here, derivative of this section here’s a quotient rule that equals this right here mark that down in your paper and here’s the answer log of 5 e times this part here. Pretty neat huh? EveryStepCalculus.com. Go to my site, buy my programs and pass calculus and subscribe to my channel if you want to hear and see more videos.

Graphing Equation to a Tangent Line on TI-89

February 2, 2014 by Tommy 1 Comment

Graphing Equation to a Tangent Line with the TI-89: Raw Transcript

See the original Tangent Line problem done here.

I’m going to graph this for you right now and show you what actually has happened so we’re gonna quit we’re going to goto 3 and we’re gonna quit go back to the home screen we’re going to clear the calculator screen by pushing f1 and 8 which clears the whole screen and were gonna graph we’re gonna put the main…that means the Gold Key here yellow key and F1 so we got the graph points gonna enter gonna graph the original function which is 10 times x divided by X squared x squared plus 1 and we’re going to graph it, that would be the big yellow key and up here it says graph so we’re gonna graph it ok, that’s the function notice the smooth parabolas, if you did this close up which I’ll show you in a second this is all smooth parabolas it’s all calculus can deal with is smooth parabolas now we’re gonna we’re gonna go back and we’re gonna put in the the equation for the tangent line we found so we’re gonna go back to F1 again and we’re gonna put in here we found out that the slope was 5 actually equation was 5, it was 0 times 1 plus 5 so that’s the equation for the tangent line in this. and then we’re gonna graph it again and see what happens you notice that when the slope is 0 you have a horizontal line that’s a big deal in calculus so remember that any time the slope is 0 they always have you make the function equal 0 first derivative and what, and so that means that the line can only touch a graph at one point and so you notice that this is the maximum okay this is the maximum remember that maximum minimums when you graph a function well here it is when your horizontal line touches this graph it only one point and that would be right here now we can take the cursor and you notice this little dot here comes up we can take the cursor we can go up here we can keep going up to x equals of course x equals 0 here’s y equals 4.7
we can go right to five and then we can move it over and we can we can zoom in on that
notice so we can press f2 and then press number 2 here and at that point we’ll press Enter and you notice that you can zoom in at those points pretty neat there’s that point there here’s straight line coming over now this is what we found: okay and you have gotten a 100 percent on this line plus may be understood a little bit better so pretty neat huh? EveryStepCalculus.com go to my programs enjoy my programs pass your calculus class and also subscribe to my blog or future videos to understand or not understand calculus and yet pass your test

Equation to a Tangent Line Test Question on TI-89

February 2, 2014 by Tommy Leave a Comment

Equation to a Tangent Line Video Example

Below is a real test question from a student that we will solve and later graph it on a future post.

Equation to a Tangent Line Question

Equation to a Tangent Line: Raw Transcript

See how to graph the answer to this problem HERE

Hello this is Tom from every step calculus dot com
Going to show you how to do the equation to a tangent line
and a little bit about that I’m going to graph it for you too
have you maybe understand a little bit better even though we’re really
interested in passing our
tests and moving on never to touch calculus again
um, let’s get started you have to put index eight because of calculus one that’s in
my instructions
press Enter and
you notice this is the test problem actual test problem that was on a sheet
this person got nothing on this problem
where he could have probably got 20 points or ten
but its find the equation from the tangent to the curve of y=10x over
x squared plus one at the point 1 and 5 you’ll notice that this is a tough
question
also for calculus one in my opinion from professors it
should be calculus 2 or something because again you’re you’re having to do
the quotient rule notice you got 10x divided by x squared plus 1 so you
do the quotient rule first and then go to the
my program for equation of a tangent line
to figure out the equation for that y equals mx plus b
so let’s do that we’re going to we’re gonna gold scroll to
you have to know this stuff a little bit about calculus to be able to do the
programs but that’s okay
what we’re after here after the quotient rule
okay quotient rule scroll down the quotient rule
here it
is
write this down in your paper right very small nerds
write very small and sloppy because they are confident they know calculus and
and so that’s all of what they do
in my experience so anyways you notice you have to put again the
parenthesis with the division sign between and so we have two functions
where going to press alpha first to get to the so we can put the
function in my entry lines here
so we’re gonna put
0:00
parenthesis, we’re going to put the parenthesis
10 times x
close off the parentheses
divided by parentheses
X squared
plus one
close off that parenthesis show you what you’ve entered again
there’s f of x equals 10 of x g(x) equals
x squared plus one and we do the computations
write this on your paper so you look like a genius
and here’s the answer
10-10x squared over x squared plus one squared
okay notice that the quotient rule will always has an x squared or
square in the bottom in the denominator
so now we’ve got that in our paper now we need to go
to the main menu the answers number two
and we need to scroll to equation of a tangent line
you need to practice with my programs a little bit to
understand the menu and stuff and we go to equation tangent line
and we’re gonna enter our function
alpha again
10 times x
just an ordinary function add it like you would
into the calculator you don’t need parenthesis like we did to get the quotient rule or
the product rule divided by, of course division always needs a
needs a parenthesis in the in the denominator
that’s x squared
plus 1
and I show you what you’ve entered and they’re asking us to find the
equation to a tangent line at point 1
X they give you a .5 but that’s really nonsense because the
to do the equation gives you the that point which I’ll show you in a second
so we put alpha 1 and I ask if you
made a mistake on that we say it’s okay and so here’s the
slope of course of a tangent line, or slope of a line in the…
is a derivative of the function that’s all it is
it’s all I’ve ever figured out it is, so, It’s the slope of a line here it is if you add an
X value to it which we will do in a second which is one your gonna come up with a
certain amount
for y and so here’s the
here’s the first derivative and X equals 1 notice I put the one here
f of prime of 1 and then you’re gonna enter one in all these places were
x was you write that on your paper you generally put
parenthesis around here but I couldn’t do that in the programming so I had to put
quotation marks
to make it work and you come up with the slope of
0 m equals 0 so now x equals one we need to find out what
what y would be so we
put that into the original function and turns out y is equal
to 5 which is what they told you in the first place x and y is equal to 1 and 5
now we figure out the equation
and if y equals five then y equals mx plus b
five equals mx plus b and 5 equals, there’s the slope
m which is 0 and here’s X which is 1
and we’re gonna find what b, b is equal to 5 minus
0 equals 5 so the equations of tangent line is y equals
0x plus 5
um….pretty neat

Implicit Differentiation Test Question

February 1, 2014 by Tommy Leave a Comment

Here is an example of a Implicit Differentiation test problem solved by the TI-89

Raw Transcript

Hello this is Tom for EveryStepCalculus.com again. I’m gonna do implicit differentiation, and this is a test problem that a person sent me and tried. Didn’t do very well at. Would have done well with my program but I’m gonna show you how to do that.
or how it would have been solved if he had my programs um… index 8 to get to my
menu
and we press enter, were already on implicit differentiation
so I’m going to go there you can scroll that and
gonna add the
function, or equation
you have to press alpha before you enter anything in my entry lines in my
programs
Your going to press alpha, and put in
X cubed
plus 3
times X squared
times y
plus y cubed
equals 8
It’ll show you what you have entered
you can change it if you want, I say it’s okay
and your taking the differentiating both sides
d/dx of x cubed, d/dx of 3 times x squared times y, d/dx y cubed and 8
this is product rule because you have a times sign between there
I do each one for you
d/dx of x cubed is equal to 3x squared
you write all this on your paper d/dx of 3 x squared times y
I use the product rule…
and I show you that if you wanna the all
the formula for product rule, here’s the answer
6xy plus this
dy/dx of course and then
y cubed etc…
mark everything down on your paper and then the other side d/dx of 8 is equal to
0 this is the equation here
your separating dy/dx in certain sections
keeping the other ones without dy/dx in another section of the equation
and so here’s your answer
-3x squared minus 6xy you write all this on your paper
you get an A in this problem pretty neat huh? every step calculus dot com goto my site,
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Product Rule Test Question on TI89 | Every Step Calculus Video

January 19, 2014 by Tommy Leave a Comment

Product Rule Test Question on TI89

Find y

y=(3x-2)(5x^3-x^2+1)

product-rule-test-question-ti89-calculus

Raw Transcript

Hello this is Tom from every step
calculus dot com wanna show you how my programs work with the product rule
for Calc 1 and how easy it is,
how sure it is, and let’s get started
have to put index eight into the entry line here to get to my menu which you’re
instructed to do in my instructions
press ENTER here we’re already at the product rule
you see quadratic formula quotient rule all kinds of things you can choose from my
menu
you go up and down my menu whatever with the cursor
here we’re going to choose product rule product rule
any any two functions separated by a times sign
is the product rule for differentiation
and if it had a division sign in there you’d be doing the quotient rule
so you have to know some things about calculus and have to remember
certain things and that’s wonderful so keep that in mind is very important you
write all this down on your paper
you don’t write the formula, the word formula, the product rule you write
these
down on your paper to remind you as you would during a test or whatever
homework
what you’re doing and
then we’re going to enter our function you have to press alpha before you enter
anything into my entry lines here in my programs you
pressed alpha, we’re going to put the quote here you have to do an example of what it is,
it has to be in parentheses
with the times sign in between first parentheses we’re going to put the function in
of this test problem, this is an actual test problem from some person who didn’t get
do very well on the test he would have gotten certainly five points on this
problem if he did it correct
and points are essential being that
calculus testers score on partial credit and the class curve
so we put the left parenthesis
in there and we put 3 times
X minus
2, close off the parenthesis, put the times sign in there
put the left parenthesis in the next function g of x, which is
zero
times x
minus X
squared plus 1
close off the parentheses I always show you what you’ve entered
make sure you entered it correct, if you didn’t you can change it
I say it’s okay
f(x) 3x -2 g(x) is 5x cubed minus
x squared plus one write this on your paper and
you’re working out the formula just like this
exactly like that all this
on your paper exactly but the answer you can if you want
here’s exact answer pretty neat huh? every step
calculus dot com goto my site buy my programs certainly subscribe to my
future videos and blogs
on calculus

Cosine Taylor Series Solved on TI-89 App | Every Step Calculus

January 13, 2014 by Tommy Leave a Comment

Cosine Taylor Series Solved on TI-89: Raw Transcript

Hello everyone this is Tom from every step calculus dot com
gonna do the Taylor series for Cosine of x
and let’s get started we have the index nine here to put in our
entry if the calculator to it to my menu
and we’re gonna
I’m gonna go up in get to the bottom of the alphabet and scroll up to to Taylor
Maclauren series
here it is here
and I tell you a little bit about the
parameters for instance when you enter 0 for
a in the formula and N the number of derivatives that you take
and of course one of the things for Taylor series and maclauren is that you know
you have to have repeating derivatives
here is the formula for the maclauren series
and for the Taylor series were going to enter our function we have to press alpha before you
enter anything in here
gonna go alpha and second cosine
of x close of the parentheses
and press enter and we’re gonna do it at
alpha, lets say 2
that’s centered at 2
here’s the Taylor series for you write that down here’s the first 5 derivatives
cosine of X and we’re doing it at the
X equals two here’s the answers there
write that on your paper we add the
factorials come up with these answers
write all this down exactly as you see it is important
here’s the answer
pretty neat huh.. every step calculus dot com go to my
site buy my programs and
while your there subscribe to future
programs or blogs

Sine Taylor Series Solved on TI-89 Video

January 13, 2014 by Tommy Leave a Comment

Sine Taylor Series Solved on TI-89: Raw Transcript

Okay this is Tom from every step
calculus dot com I’m gonna do the Taylor series with
sin of X
and let’s get started you put index
9 into the entry line here
the and I give you instructions on how to do that
press ENTER here and we’re gonna scroll down to
I going to scroll up because closer to the end of the alphabet then in the middle
and I’m gonna go to Taylor
maclaurin and press Enter
and
the ask for if they ask for maclaurin and then you’re gonna put zero in for a
otherwise you can put any number in for a actually a
is the X value on the function that you’re gonna
approximate the slope of a line at
here’s a formula for the Maclaurin series
and
for the Taylor series right these all on your paper all the time
look like a genius enter the…you have to
press alpha first before we do anything on our entry lines here’s I’m going to Press alpha
and let’s see sine
second sine of
X close up parentheses
press enter
and centered at let’s say
3 alpha
3 I always show you what you’ve entered, you can change it if you want I say it’s okay
here’s the formula it’s a Taylor series because it’s not zero for a
understand they have to be derivatives have to be
on going one after the other
that’s part of the Taylor series working
write this on your paper this is the first five derivatives of that
and then we’re going to compute the
derivatives at 3 the point we want the
slope of a line to be in that function
and we’re going to have a factorial here 2_3_4_5
to be computed at that we’ve come up with these answers here
write all this on your paper it’s all-important
and here’s the answer
cosine of 3 x minus 3
minus sin of 3 times x
minus 3 squared divided by 2 divide by 6 by 24 by 20
Pretty neat huh, every step calculus dot
com subscribe to my
site and me so you can get other
important events coming up
programs and blogs

Maclauren Series Solved on the TI-89

January 13, 2014 by Tommy Leave a Comment

Raw Transcript

Hello again this is Tom from everystepcalculus.com and I’m going to do a Maclauren Series for you at sin(x) right now. Let’s get started you enter i_n_d_e_x and 9 in here and you get my menu comes with instructions when you buy my programs um..press enter here and we’re gonna scroll to Taylor and Maclauren in the menu. Here’s Maclauren series formula n is the number of derivatives you’re taking I’ve stopped it at five in these programs and a is the point and a function where you’re going to approximate the slope of a line running into the function alpha sine of two times X and add zero cuz we doing the Maclauren series Alpha zero, show you what you’ve entered,you can change it if you want I show you the formula for Maclauren series and we do the computations this is the first five
derivatives inside 2x and then were gonna put zero in here for x and we’ll work the derivatives with that here are the answers here write all this on your paper we’re going to use the factorials here
of what we just computed and these are the answers here and you write this on your paper all very important exactly accurate and here’s the answer 2 of x 0 -4x cubed o 4×5 over 15 pretty neat huh… everystepcalculus.com. Go to my site by my programs and pass calculus don’t forget to subscribe to the site so that you can see other programs that I design and blogs

Calculus Final Solved Question 5 | Every Step Calculus

December 12, 2013 by Tommy Leave a Comment

Calculus Final Solved: Question 5

Calculus Final Solved Question 2 | Every Step Calculus

December 12, 2013 by Tommy Leave a Comment

Real Calculus Final Solved with TI-89 App: Question 5

Integrals on TI-89 Calculator

November 4, 2013 by Tommy Leave a Comment

Use the TI-89 Calculator for Step by Step Integrals

My name is Tom and I program TI-89 calculators to make Integrals much easier step by step and showing all work.

Here’s just some of the Integral problems solved with my TI-89 Calculus App:

Definite Integrals
Indefinite Integrals
Antiderivatives
Integration by substitution
Integration by Parts
Partial Fractions
Differentiation

The programs are a compilation of midterms, finals and homework from college calculus classes 1,2 and 3 all over the United States. The app shows work for calculus solutions line by line at your own pace so you can write it down on tests, homework, whatever.

You get all the calculus 1,2 & 3 programs below for the price of a serious happy hour. That all four years of calculus, updates forever included.

100% Guaranteed or your money back

LEGENDARY SUPPORT:

Phone Support (my favorite) | Email Support | Facebook Support | Twitter Support

I do it ALL and it is IMMEDIATE!

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See the original Tangent Line problem done here.

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See how to graph the answer to this problem HERE

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Use the TI-89 Calculator for Step by Step Integrals

My name is Tom and I program TI-89 calculators to make Integrals much easier step by step and showing all work.

Here’s just some of the Integral problems solved with my TI-89 Calculus App:

You get all the calculus 1,2 & 3 programs below for the price of a serious happy hour. That all four years of calculus, updates forever included.

100% Guaranteed or your money back

LEGENDARY SUPPORT:

Phone Support (my favorite) | Email Support | Facebook Support | Twitter Support

I do it ALL and it is IMMEDIATE!

Related Rates Test Question: Two airplanes pass each other in flight at 9:00 AM.
One is traveling East at 90 mi/h. The other is traveling South at 180 mi/h. How fast are they
separating at 11:00 AM?