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You are here: Home / Archives for Professors

What Calculus Professors don’t tell you about e^(x)

October 11, 2012 by Tommy Leave a Comment

One of the toughest things to do in calculus is to recognize or recall what to do with a given problem in order to solve it. Professors tell you about the problem their trying to teach but they don’t tell you about the subtle differences, what to do if this happens or is changed.I was programming – integrating e^(x) problems on the Titanium or TI-92+, or Voyage 200, for you folks using integration by parts and was really proud of myself – the step by step answers for most problems were coming up using the formula u*v – ∫(v*du) — all of sudden there were wrong answers compared with what the calculator was coming up with using its integral program or system.  Why??  So here’s what I find, and have written another program to handle it. Remember I don’t program to learn or teach calculus – I program to pass the pathetic tests, to pass the class, and get hell out of there, never to touch the subject again. So:Anything with e^(x) or e^(ax)   (“a” being some arbitrary number) even when connected to sin(x) or tan(x) or ln(x) etc is an integration by parts problem.

However:

Integrating anything with e^(x^2), e^(3x^2), e^(3x-1), e^(5x+6) is U- substitution.

To make it clear — if there is an exponent within the exponent of e, or if there is a minus sign or plus sign within the exponent of e you are using U- substitution.

Now isn’t that fun!!   What professor told you about that in class.  When I program this stuff  – I (and the program) have to know those differences, the program has  to work line by line, step by step with the best system possible to solve the problem logically and correctly. Enjoy my programs!

Filed Under: Professors Tagged With: e^(x)

What is Calculus anyway?

August 13, 2012 by Tommy Leave a Comment

To me this stuff is never taught in Calculus Class but should be taught and reviewed over and over again.  As we struggle with the concept of Calculus – and why we’re required to study it in college to the extent they teach it (me as an electrical engineering student at the age of 50, 3 semesters) – and ponder over the seemingly insane extent to finding derivatives and integrals that the classes get into – the same question appears for most of us – what the hell is calculus, what’s a derivative, what’s an integral, and so what?

Sir Isaac Newton (1642 – 1727) (lived 85 years) born in England, never married (no wonder), had no children that we know about, is credited with discovering Calculus along with –  Gottfried Wilhelm Leibniz (1646  – 1716) (lived 70 years) Born in Germany who also came up with the way we notate calculus today such as the integral sign ( ∫ ), and dy/dx.

 

Lagrange invented the f ’(x) notation (derivative of   f (x)  )

Leibniz invented the “y = f (x)” notation and the definition of a derivative as:

 

f (x + ∆x) – f (x)

lim       ——————–

∆x→0      (x + ∆x) – x

 

Notice how close the above is to the “definition of a derivative” or “difference quotient” that I have programmed and exampled on YouTube for you:

 

f (x + h) – f (x)

lim       ——————–

h→0               h

 

Newton worked on solutions in analytical geometry of drawing tangents to curves (differentiation) and defining areas bounded by curves (integration), so:  If somebody asks you what is calculus you say:

 

Calculus is the study of tangent lines to curves (differentiation) and areas under curves (integration); to me It’s that simple.

 

However my gripe is that it should be condensed and taught only for one semester – unless you’re a math major – There has to be much more important things to teach an engineering student in that field – in those extra two semesters – than tangent lines and areas. It’s hard to believe for me that after programming and studying the quotient rule, product rule, integration by parts, transcendental derivatives and integrals and all else that comes with finding a derivative, for all these years – that when you solve for x in that derivative you come up with a number and that number is the slope of a line.  Not a tangent line yet oh no!! – you have to go to my program of “ tangent line to a curve” to get the line to be placed on that tangent point on the functions curve.  The number you get after solving for x in the derivative lets say 15, you go 15 notches up on the y axis and 1 over on the x axis, draw a line down through (0,0) and that’s the slope of that line and what you found. After all that!!

 

Another thing is that calculus with regards to derivatives only works with functions.  The actual function is the trick, and that’s found by experimentation to be able to come up with data points (x,y) or (x,y,z) to be able to graph it.  When a professor says that the first derivative is also velocity, which is true, – making you think that calculus discovered it –  the thing Is – velocity has already been found at that point or any point on the curve by the genius who designed the function in the first place. Incidentally that 15 number above would be 15 meters per second at that computed point on the curve with regards to velocity, slope is just a number.

 

Like John Goodman says in the Big Lebowski, “am I wrong?”

 

One more thing before I let you go – from Wikipedia

 

Leibniz became one of the most prolific inventors in the field of mechanical calculators. While working on adding automatic multiplication and division toPascal’s calculator, he was the first to describe apinwheel calculator in 1685[4] and invented theLeibniz wheel, used in the arithmometer, the first mass-produced mechanical calculator.

 

Is it any wonder why I programmed the calculator for my own use and now yours – I’m in good company – with the following from wikipedia regarding first mechanical calculators.

 

“The desire to economize time and mental effort in arithmetical computations, and to eliminate human liability to error, is probably as old as the science of arithmetic itself. This desire has led to the design and construction of a variety of aids to calculation, beginning with groups of small objects, such as pebbles, first used loosely, later as counters on ruled boards, and later still as beads mounted on wires fixed in a frame, as in the abacus. This instrument was probably invented by the Semitic races and later adopted in India, whence it spread westward throughout Europe and eastward to China and Japan.
After the development of the abacus, no further advances were made until John Napier devised his numbering rods, or Napier’s Bones, in 1617. Various forms of the Bones appeared, some approaching the beginning of mechanical computation, but it was not until 1642 that Blaise Pascal gave us the first mechanical calculating machine in the sense that the term is used today.”

 

Enjoy my programs,

 

Tom

everystepcalculus

Filed Under: Calculus 1, Professors Tagged With: Calculus App, definition of a derivative, derivatives, first day of calculus, point slope form, step by step calculus, TI-89 Titanium, what is a derivative

My Programming History

August 9, 2012 by Tommy Leave a Comment

About 19 years ago (1993)  I started college at San Diego State at the age of 50.  Electrical Engineering Major.  Calculus one was miserable for me and I actually flunked it, then re-took it the next semester and got an A. The semester after that was Calculus II, when we were required to purchase the TI-92 calculator, which had just come out from Texas Instruments.  Cost was around $185 I think.  I was pissed about buying that because of the cost and I thought my old HP calculator would work just fine.   Turns out that the TI-92 purchase certainly helped my college career in all my classes and has allowed me to sell my programs for all these years. First I found out that it had a word processor in it and so I started to scan my homework, study problems and whatever into my computer and via Graph-Link was able to download that – as notes – into my TI-92.  I could find topics via word search and it helped me somewhat for tests.  Anything like that however is like an open book test where one has to find the problem, read it, then add your variables and try to get the problem correct.  To me a very slow process and in many instances to slow to even finish all the problems in a test.  Then one day – in desperation for a better system – I happened to read and discover,  in the TI manual, the subject of programming the calculator.  I discovered the fabulous programming capabilities of the TI calculators. Wow what a system for me or anyone. I had an edge over anyone in class from then on, and even better for me, was the ability to never forget a problem. To desperately avoid the waste of time system in college,  of cramming – testing – and forgetting – (CTF) which is the main system of college even today.  I can still do all those problems;  Calculus, Physics, Electronics, Lasers, Optics, even Geology problems. Even if you took fabulous complete notes in classes and college you still couldn’t add the variables and complete a problem, after a while, without out again studying. When you are young like most college students, you don’t know you are wasting time, and don’t care for that matter, but when you attend at the age of 50 its a different story, CTF and wasting time is, and was, not acceptable. I got so good at programming the TI calculators, that  I wrote a manual on programming and used to sell that. However after the Titanium came out that ended.  I would have never found programming, to any helpful extent with TI Connect and the TI-89 calculators, Titanium included. The programming system is still in those calculators but extremely impractical.  Wouldn’t have happened.  I still think that the greatest calculator ever from Texas Instruments was, and is, the TI-92 Plus calculator. Better than the Voyage 200, the NSpire Cas or the Titanium.  The Nspire Cas Cx is pathetic, with no practical programming capabilities to my knowledge.  Anyway enjoy my programs, there is nothing like them.

Filed Under: Calculus 1, Professors

Critical numbers and critical points in graphing

August 1, 2012 by Tommy 2 Comments

It seems that most calculus tests I receive to check my programs with, and with regards to graphing a function by hand, they always have you find: ” critical points”.  Then the answer is always just what “x” equals.  You factor the first derivative f ‘(x), find the value of x or x’s and mark it down on your test problem to get it correct x=2 or x=5 or whatever.  If I was your professor (you wish) you’d have gotten only partial credit because you found the “critical numbers” and not the “critical points”.  However, critical points are actually the value of (x,y).  You find the values of x, from the first derivative, plug those values into the original function f(x) to find the value of y, and you have the critical point or points (x,y).  When tests ask for critical numbers the professor actually means critical numbers.  There is a difference!! In my program I find both for you critical numbers and critical points (step by step of course) and leave it up to you as to what or how your professor teaches this, in most cases teaching it incorrectly, what else is new?

Filed Under: Professors Tagged With: calculus, Critical numbers, Critical Points, definition of a derivative, derivatives, first day of calculus, step by step calculus, what is a derivative

How Professors teach compared to my programs

March 18, 2012 by Tommy 3 Comments

Here is what you get as an answer usually when you ask a question on Calculus or even Physics in my experience and evidently the asker was satisfied. The person answering is a professor at a college. This girl asked on line for help on what the derivative of 4cos(5x-2) was.  This is a chain rule problem.  How would you like it answered?

www.everystepcalculus.com

Tom’s Programs for the Ti Calculators Answer!

 

Chain Rule:

 

h(x)   = f [g(x)]

h’(x)  = f ‘ [g(x)]*g’(x)

 

= 4cos(5x-2)

= (4)-sin(5x-2)*d/dx(5x-2)

= (4)-sin(5x-2)*(5)

= (5)(4)-sin(5x-2)

= -(20)sin(5x-2)

Best answer as selected by question asker.                                                  

For a function f(x) = g(h(x)), express h(x) as y.

Then f(x) = g(y), f’(x) = [d {g(y)}/ dy]*(dy/dx).

Here we have to find the derivative of f(x)= 4 cos (5x-2).

Let y=5x-2, this gives f(x)= 4 cos y

f’(x)= [d (4 cos y)/dy]*[d(5x-2)/dx]

We also know that the derivative of cos x= -sin x.

=>   [d (4 cos y)/dy]= -4 sin y

[d(5x-2)/dx]= 5

Therefore f’(x)= [d (4 cos y)/dy]*[d(5x-2)/dx]

= (-4 sin y)*5

=-4*sin (5x-2)*5

=-20 sin (5x-2)

Therefore the derivative of 4 cos (5x-2) is -20 sin (5x-2)

 

Filed Under: Professors Tagged With: chain rule quotient rule, the chain rule, trig function

Point Slope Form: The relation to calculus

March 14, 2012 by Tommy 1 Comment

The equation of a line to a point on a curve (point slope form) includes the slope and the position of that line on that curve function.  It’s better than the derivative because the derivative only tells us the slope. Again in Algebra the professor forgot to tell us the importance of that and the relationship to the derivative. Didn’t make it interesting enough to sink in and how it relates to the real world.

You have a function.  Has to have x^2 in it to be a curve from my understanding,  Example y or f(x) = 3x^2

Graph that and you have some form of curve in this case a “valley” parabola, (my own word), -3x^2 and you have a “mountain” parabola (again my own word).

Pick any point “(x,y)” Example: (3,12)

Point = (3,12)

x = 3

y = 12

 Find the derivative:   f(x) = 3x^2

f’(x) = (2)(3)x^(2-1)

= 6x^(1)

= 6x

Compute the derivative at the point “x”

f’(3) = 6(3)

= 18 = m = slope

Point slope form = y = mx + b

y   = 12 so:

 12 = mx + b

m  = 18

12 = 18x + b

x    = 3  so:

12  = 18(3) + b

= 54 + b

b    = 12 – 54

= – 42

y    = mx + b

= 18x + -42

 If you graph this equation along with the original function you’ll see the tangent line to that point on the curve

The slope =  18/1   (rise over run)

The angle of that tangent line = tan^(-1)(18/1) = 86.8 degrees

(make sure your calculator mode is in APPROXIMATE and DEGREES)

Fabulous and exciting, right?  lol Tom

p.s. You’ll love my programs

Have a test or quiz on point slope form? Here is a video example using the programs on the TI-89 calculator: (Click Links below)

Point Slope Form Calculator

Point Slope Form Given Two Points

Filed Under: Calculus 1, Derivatives, Point Slope Form, Professors Tagged With: algebra, calculus, derivatives, point slope form

First day of calculus I

March 14, 2012 by Tommy 2 Comments

In my first day of calculus I – the chalk was flying.  That professor started with the fundamental theorem of calculus, probably said “if it exists” a hundred times, and never let up from then on. It got worse from then on and never better. I, with others – I’m sure – sat there in disbelief and in a fog.  I was 50 years old that day. I remember 3 semesters later I turn to the guy next to me and ask, “What the hell is a derivative?”  He whispers,  “I think it’s an angle of a line or something”.

Try it yourself go up to any one of your friends, ask them first if they’ve taken calculus and then ask them what a derivative is, and see what the say or don’t say.  That’s the way all of my professors taught in my experience of college, I never enjoyed one class.  If it was me – and my inability to learn in a class – that kid would have told me what a derivative was without any question as well as others in the class, however nobody knew (I asked several others after that kid) they didn’t know either. We were all three semesters into calculus and didn’t know what a derivative was. What the hell is that?  Isn’t knowing what a derivative is, in no uncertain terms, more important than the fundamental theorem of calculus???

Filed Under: Calculus 1, Derivatives, Point Slope Form, Professors Tagged With: definition of a derivative, derivatives, first day of calculus, what is a derivative

Professors

February 16, 2012 by Tommy Leave a Comment

In my experience professors teach theory and proofs and then test on mechanics which somehow (the mechanics)  get lost in their lectures.  Also, maybe understandably,  because of tenure and boredom in their jobs they might tend to get away from – or not get down to – the struggling  students level when they teach. In my programming of a problem, I can’t skip steps to the solution, somehow every step must be addressed and accomplished.  That’s what make my programs as designed so essential, helpful and perfect for the student.  Enjoy my programs, Tom

 

 

Filed Under: Professors

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 Tommy,     Great talking with you last night. I already liked you for developing this “most excellent program” but after our conversation I concluded you to be a great guy. I’ve been playing with this program most of the night, took in a few “z’s” and am back for more. This program really is superb. I did, however, notice that for some unknown reason when I attempt to do Relative Extrema’s and Trajectories that both programs came up as “Program not Found”. I’m not sure if I will be encountering the Trajectory stuff in this semester of Calculus but I do have a test this Thursday that includes Relative Extrema. Any suggestion, oh Master of this great creation?! I’m going to be gone most the day but should be home late afternoon if you got time to call. Same number (843-xxx-xxxx). That’s Myrtle Beach, 3 hours ahead of you and more golf courses than you can shake a stick at. Thanks    -Joe

Wow! Awesome! These are great, so great, thank you!            -Kristen

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