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You are here: Home / Archives for Integrals / Integrals

U Substitution Calculator

March 6, 2015 by Tommy Leave a Comment

Raw Transcript

Hello, everyone. Tomfrom everystepcalculus.com and everystepphysics.com. I’m already at U Substitution. You scroll with these cursors, here to get to whatever in my menu that you’re interested in. You have to press alpha before you enter anything into these entry lines, here. And the problem is Alpha x times the square root of x squared plus sixteen. close off the parentheses. X times Square root of x squared plus sixteen. That’s cool. I always show you what you’ve entered. Now, how are you going to go about solving this yourself? Okay, think about it. In U Substitution notice this is a exponent of two, this is an exponent of one. okay. If the x has one less exponent than the inside of the parentheses, this is a U substitution problem. For instance, you should always in your mind to do with the derivative of something in the parentheses in Calculus. That’s one of the big deals and big tricks. So this is 2 X then. And there’s of course no derivative 16 at zero. So it’s 2x
Well here’s an X on the outside. Well, we can do something with the 2 to make
that x dx. So generally what I do what and what you should do. I say it’s okay because we’ve entered it right. You should rewrite the problem okay. So you rewrite the problem.
Square root of x squared plus 16 and you put the x dx over here so you can kinda see that you’re trying to match that somehow, okay. So then U equals x squared plus 16. Well then du equals 2x dx, okay. We take that 2 and the du divided by 2 through Algebra. And we come up with x dx. Notice that this matches the previous match of the function. so that a course you is equal to this group experts 16 So we have the Integral of u and of course the square root, in calculus you always change it to 1/2. It was a cube, it could be 1/3. If it was the 15 root, you’d be 1/15, okay. That’s Algebra 2. I mean also. So and then you have the DU divided by two so that’s a constant, you have to bring outside the integral, here. I do that for you. Here’s the 1/2 outside the integral and then we do the U to the 1/2 inside and
then integrate that part, okay. And that turns out to be this this this and the answer is 1/3, etc. So, have a good one. everystepcalculus.com

Filed Under: Integrals

Critical Points-Work Shown on TI-89-Video

February 9, 2015 by Tommy Leave a Comment

 

Transcripts

Hello, Tom from everystepcalculus.com,and everystepphysics.com. A problem in calculus dealing with critical numbers in critical points of a function. Let’s do it. Index 8 to get to my menu. Then your going to scroll down to critical point or numbers.I always have you start a graph on your paper. When you enter the function you have to press Alpha before you enter anything into these entry lines. Your going to press Alpha X cubed minus 3 times X. I always show you what you’ve entered. You can change it if you want. I say it’s okay. And we’re gonna choose number five, critical points.

Filed Under: Integrals

Triple Integral: Work Shown on TI89-Video

February 4, 2015 by Tommy Leave a Comment

Screen shot 2015-02-04 at 12.32.17 PM

 

 

 

Transcripts

Hello again, everyone. This is Tom from everystepcalculus.com and everystepphysics.com. I’m going to do a Triple Integral for Calculus 3 right now. This is an example of a Patrick JMT, my favorite instructor on the internet, on YouTube. So I’m going to show you how it works on my program. I don’t know anybody can do that problem. He can do it because he’s a genius. But for us students,etc. How do we do it? Let’s get started. Index 8 to get to my menu. I’m going to scroll up because I can go to the bottom of the menu then instead of going down quicker to go to the T’s section. And we’re going to choose Triple Integral. And we’re going to enter our function. You have to press Alpha before you enter anything into these entry lines here in programs, okay. Alpha x times sin of Y. I always show you what you’ve entered. You can change it if you want. And we’re going to use the order of integration which is dx, dz, dy which is in the example. You have the other choices in case that’s given on test also. And we’re going to enter region q. Enter these limits. This is Alpha 0 for the x one Alpha square root of 4 minus z squared I made a mistake so I gotta go back. Choose number 2. Alpha 0, Alpha square root of 4 minus z squared. Close up the parentheses. That’s better. I say it’s okay. Next one for the y is Alpha 0. Alpha pi. That looks okay. and Alpha 0 for z. Alpha 2. That’s okay. So here’s what you write on your paper. The way you write it with triple integral with dx dz dy order of integration. Here’s the function in here. So you’re going to do the dx first and you put this over here with these lines. Showing you’r doing a range over this integration here. And here’s the integral of the first function okay. And if x equals the upper range. I show quotation marks here but you put you put parentheses in there. Because you’re substituting this amount for an X in the integral. And it equals this, minus sin, etc. And then we do the lower integral. X equals 0 and there’s 0 and you put parentheses around this instead of quotation marks, okay? And here’s the answer, you have the upper range minus the lower range equals this right here. So that becomes the new integration function. And I show you that here. dz dy is left, okay. So now we integrate that. Come up with this. Minus sin, etc. over this range here 0 2. Add z equals 2 Here’s the answer here. And z equals 0. Plug these in for all the Z’s in the problem. And the answer is this. 8, the upper range minus the lower range is 8 sin y divided by 3. Now we’re going to use that for the integration function. With the range of 0 and pi. At y equals pi minus 8 cosine is 8 thirds.

Filed Under: Calculus 3, Integrals

Find the Gradient of Point-Video

November 23, 2014 by Tommy Leave a Comment

Filed Under: Integrals

Gradient Solver at Point (1,2) Video

November 17, 2014 by Tommy Leave a Comment

Filed Under: Integrals

Magnitude of a Vector P&Q Points-Video

October 30, 2014 by Tommy Leave a Comment

Filed Under: Integrals, Vectors

Equation of a Plane Using 3 Points-Video

October 29, 2014 by Tommy Leave a Comment

Filed Under: Integrals

Solving Equation of Plane 2 Points-Video

October 29, 2014 by Tommy Leave a Comment

Filed Under: Integrals

Eliminate the Parameter XYZ Plane-Video

October 27, 2014 by Tommy Leave a Comment

Filed Under: Integrals

Divergance at a Point Curl Solver-Video

October 24, 2014 by Tommy Leave a Comment

Filed Under: Integrals

Disk Method Revolving Around Y Axis- Video

October 23, 2014 by Tommy Leave a Comment

Filed Under: Integrals

Disk Method Solver-Video

October 23, 2014 by Tommy Leave a Comment

Filed Under: Integrals

Solving Definite and Indefinite Integrals – Q&A

August 21, 2014 by Tommy Leave a Comment

Dear Tom,

I would like to know if your program also solves integrals consisting only of symbols like x, a or b in both definite and indefinite matters?

Example:

definite-integrals 

 or

indefinite-integrals

 

Would solving does definite integrals be possible using your programs showing the solution process step by step?

Kind regards,

Ben

Answer 

The first integral, sounds like your professor didn’t teach you, so you will want my programs to teach you or me to teach you. A common endeavor in my experience. When you see the da that’s “with respect to” in other words, you are integrating that integral with respect to “a”.  In my programs you’d change all the “a’s” to x”s.

Now could you solve the integral if it looked like:       

  x                  x

∫ (1/x)dx   or ∫ (   1/[(c+b)-(k+x)]  ) dx

o                   o

Now these would never appear on a test unless your professor demonstrated them on the black board, so they are either homework or experimenting off the internet. Both integrals are definite integrals because they show a range to integrate over. When you solve the integrals you have the area under that functions curve. That’s all integrals do is solve area under curves. You can graph 1/x on your calculator and you can see what the first integrals function looks like. Now, anytime you see a function without an exponent in the denominator, it is a natural log answer. The reason is is that you can’t integrate term with a division sign.  

In this case the x has an exponent of 1 (  x^1), you always have to move the denominator to the numerator to eliminate the division sign before you can integrate. If you move the x^1 to the numerator to eliminate the division sign it becomes x^(-1) so when you do the integration process which is always add 1 to the exponent and divide the term by that answer, However when you add 1 to a -1 you get zero, and any term to the zero exponent = 1, so that’s why the natural log comes in. In the first integral above = ln(x), then you can enter the ranges for x that you are given, do the top range first and subtract the bottom range to get the answer (area under the curve of the function). The second integral above you’d break it into two integrals ∫[1/(c+b)] dx which equals x/(c+b) and then the second term 1/[(k+x)]dx which equals ln(k+x). 

 

 

Filed Under: Integrals

3 Calculus Questions Solved by TI-89

March 27, 2014 by Tommy Leave a Comment

I’m really trying to figure out how to use your program with a couple different problem examples: 

“Find the following derivatives of f(x). Do not leave any negative exponents”

1. F(x)= 4^x-ln(2x^2-x)

What program can I use to solve this?

another is f(x)=2csc(x)+5arccos(x)

This is fundamental to calculus and you must start to learn it or know it.

Notice the minus sign between the terms (if a plus no difference)

This means that the derivatives of the terms are separate or individual

You differentiate each by itself and one at a time

There could be 15 more terms each separated by a minus or plus and you’d do each one separate.

So:   f(x) =  4^x f’(x) =  x*4^(x-1)  Notice when differentiating you take the exponent

Multiply it times the front of the term and take one away from the exponent.

You must do this process in your sleep and fast or you’ll have trouble passing calculus

Another Example

f(x) = 15x^7

f ‘(x) = derivative

         = 7*15*x^(7-1)

         = 105x^6

Integration is the exact opposite

You add one to the exponent first

Then divide by that new exponent

∫[105*x^6] dx

= 6+1 = 7

So:   105*x^7 / 7

     = 15x^6

Problem 1) the trig problem

Reload the attached program

First Delete the same named program from you calculator

Then reload the attached changing to “Archives” first

For the problem go to:

“trig” in my menu

Scroll to csc(x)

Find the derivative and add the 2 in the front of the answer

For arcos(x)

Scroll to cos-1 in the menu of trig

And find that derivative adding the 5 in front

“Answer the following questions about the given function: f(x)=x^3-6x^2+9

A) Find f'(x)

B) Find f”(x)

These again are separated by minus and plus signs so each is differentiated separately

f(x) = x^3 – 6*x^2 + 9

f ’(x) = 3x^2 – 12x + 0

f ‘’ (x) = 6x – 12

Notice I took the exponent and multiplied it by the front of the term

And then took one away from the exponent in each case.

Do these in your sleep!!!!!

 

Use log differentiation to find the derivative of the following function with respect to variable x.

(x^3+2)^3sqrt(2x^2+3)

Notice the “times” sign so you’d be thinking “product rule” or logs to differentiate

First it must be expanded:

I have expanded log problems to another base

But haven’t programmed to expand natural logs, but am in the process.

Should be done soon

 (x^3+2)^3  *  √(2*x^2+3

ln((x^3+2)^3)  +  ln(√(2*x^2+3)   (always you change a square root to ^(1/2)

= ln( (x^3+2)^3 )  +  ln( (2*x^2+3)^(1/2) )

=  3*ln( x^3+2 )  + (1/2)*ln( 2*x^2+3 )

Now you can choose in my menu

“log Problems”

Choose “ln(x)”

Choose “differentiate”

And add the above ln tems one at a time

Put the problem back together when finished with the individual solutions.

 

Filed Under: Integrals

Calculus Q & A

March 17, 2014 by Tommy Leave a Comment

Can the Calculus App do the Following?

F(x)=6x^-5

 F(x)= 6x^4-4x^3+5x^2

Answer:

f(x) = 6x^5    would be “derivative/algebra” for differentiation

                   or  “Integrals/Algebra” for Integration

I didn’t program this for myself or anyone because the student needs to be able to do these in his/her sleep.  They have to learn these without programming, and they are simple
The second function is separated by minus and plus signs, so each one is a separate derivative or integral with the same minus signs or plus signs.
Derivatives you take the exponent and multiply it by the front of the problem and then subtract one from the exponent:
f(x)    = 6x^5
f ‘ (x) = 5*6*x^(5-1) = 30x^4
f(x)    = 6x^4 – 4x^3 + 5x^2
f ‘ (x) = 4*6*x^(4-1) – 3*4*x^(3-1) + 2*5*x^(2-1)
        = 24x^3 – 12x^2 + 10x^1
        = 24x^3 – 12x^2 + 10x
 Now I’m not sure what you mean by “solve”?
Integrate or differentiate?

 

Filed Under: Integrals

Calculus Final Solved Question 5 | Every Step Calculus

December 12, 2013 by Tommy Leave a Comment

 

Calculus Final Solved: Question 5

Filed Under: Integrals

Calculus Final Solved Question 2 | Every Step Calculus

December 12, 2013 by Tommy Leave a Comment

 

Real Calculus Final Solved with TI-89 App: Question 5

 

Filed Under: Integrals

Optimization | Max Area Enclosed by Rectangle | TI-89 Calculus App

October 15, 2013 by Tommy Leave a Comment

 

Optimization for Max Area Enclosed Rectangle on TI-89: Raw Transcript

This is a video from every step calculus dot com
demonstrating how my progams work on a t i eighty nine titanium calculator
and other calculators in the t i system for physics and calculus problems
ok this is an optimization problem in calculus and ah with regard to finding the area
given a amount of fence which is a usual problem in calculus
ah and let’s get started you put second alpha
you push second alpha to put in the i n d e x letters
and then press alpha and put in the eight and open and closed parenthesis
press enter and you’re into the menu calculus one menu
and we’re going to scroll down here to go to fence area
and we’re gonna press enter on there and a certain amount of
using a certain amount of fence how much is them maximum of area etcetera
given one side of a river and were going to put in maybe
you have to press alpha before you put any a numbers or any
characters in these lines of my programs so well press alpha
and were gonna put maybe eight fifty for the maximum fence that you have to work
with I always show you what you’ve entered
so you can change it if you want I say it’s ok
here’s a picture of it here’s the river
and you got the x on each side and the length of the other side
and generally in a problem or a test their going to ask you find the equation
for the length, here’s the equation eight fifty minus two x
write that on your paper here’s the area function
x times w and here’s the function here
write this on your paper eight fifty x minus two x squared
we multiplied x times eight fifty we take the derivative of that
here’s the derivative eight fifty minus four x
write that on your paper you gonna look like a genius
and we’re finding a critical number really critical number is not a critical point
because you haven’t found the y you’ve just found the x value
notice we took the derivative and then did the algebra computation
to find the x. write this on your paper
and here’s what you’ve found you found two thirteen on this side
two thirteen on this side and four twenty five for the length
just in case you’re interested in that they don’t generally ask you that
but they might you plug the critical number into the
original function to get the maximum area actually you’re getting the critical point
then and you do these computations and notice
that the area is ninety thousand three hundred thirteen
square units if its feet that would be square feet
if it’s meters what ever and this actually the point would be
eight fifty for the x and ninety thousand three hundred thirteen
for the y and pretty neat huh
every step calculus dot com go to my site
buy my programs and pass calculus

Filed Under: Integrals Tagged With: Area of a Rectangle

Calculus Cheat Sheet: EveryStepCalculus.com

October 25, 2012 by Tommy Leave a Comment

ti-89-titanium-calculus-app-program-software

Use the TI-89 as the Ultimate Cheat Sheet

 

..

My name is Tom and I program TI-89 calculators to be the Ultimate step by step Calculus Cheat Sheet. The app show all work right on the calculator screen. 

The programs are a Compilation of Midterms, Final Exams and homework from college calculus classes 1,2 and 3 all over the United States. The app shows work for calculus solutions line by line at your own pace so you can write it down on tests, homework, whatever. 

 

Buy Now

You get all the calculus 1,2 & 3 programs below for the price of a serious happy hour. That all four years of calculus, updates forever included.

100% Guaranteed or your money back

 

 LEGENDARY SUPPORT:

Phone Support (my favorite) | Email Support | Facebook Support | Twitter Support

I do it ALL and it is IMMEDIATE!

 

CALCULUS 1 PROGRAMS (Scroll down for 2 & 3)

Chain Rule | dy/dx = f’[g(x)] * g’(x) | dy/dx = f’(u) * u’ | (5x²+7)^5 | sin(ax) | 7*cos(5*x^2) | (tan (5x))^5   Video Example

Concavity

cos(a * x) derivative

cos(a * x) integrate

Critical Points   Video Example

Definite Integral |  = ∫ [ f (x) ] dx    Video Example

Definition of a Derivative

Derivatives/Algebra (step by step) | √(x) | 3√(x) | 5/√(x) | 5/x | 5/8x | 5/x² | (5x)² | 5x²/8 | x(x+5) | x^½ | x^(-½) | (x²-4)/(x+2) | (x²-4)/(x-2) | (5x²+7)^5 | √(5x²+7) | (5x²+7)½ | ³√ (5x²+7) | (5x²+7)¹/³ |  sin | cos | tan

Difference Quotient   Video Example

ê(x) Derivatives

ê(x) Integrals

Equation of a Tangent Line (y=mx+b)   Video Example

Equation of a tangent line at a pt  | (y = mx + b)   Video Example

Graphing by Hand | Concavity | Critical Points | Crosses x axis | Inflection Point | Intervals of  Increase | Intervals of Decrease | Local Max & Min                                                                                                              

Local Max and Min   Video Example

Implicit differentiation | y³+y²-5y-x²  = -4  Video Example

Integrals/ Algebra (Rewrite selected & Integrate) | n / √(x) | (x² + n)² | (x³ + n)/x² | ³√(x) | n / x² | n / ³√(x) | n / x√(x) | 1/x³

Integration by Parts | ln(x)   Video Example | n*e^x   Video Example | sin(x)   Video Example | cos(x)

Intervals of Increase or Decrease

Limits   Video Example

In(x) Natural Log

log(x) Log to Other Base | Evaluate | Solve for x | Exponential Form | Logarithmic Equation | Differentiate

Product Rule | ( f (x) )( g (x) )  Video Example

Quadratic Formula

Quotient Rule | ( f (x ) ) / ( g (x) )  Video Example

Relative Extrema

sin(a*x)  Derivative

sin(a*x)  Integral

Trig & Half Angle Formulas & Identities | cos(2x)2 | 1-cos(2x) / 1+cos(2x) | sin²(x) + cos²(x) = 1 | tan(x) | tan²(x) |  Trig d/dx cos(2x)/2 | cos(2x) | cos(x) | cos²(x) | cot(x) |  csc(x) |  csc²(x) | sec(x) |  sec²(x) | sin(2x) |  sin(x) | sin²(x)

Trig d/dx Identities

U – Substitution

 .Buy Now.

Recent Testimonials Summer 2013:

Tom-    I showed my ex, who is a calculus professor, and he was waaaaaaay impressed. And he is an arrogant ass, who never helped me ever…I could tell he wanted to hate on it, but he couldnt. 

Kristin P

Tom…I think that I’m finally done with Calculus II. In the prior test I got 78 and yesterday I finished all the problem on the test. I think I should be able to remain around the same grade. Thank you so much for your help; your programs really made the difference. They didn’t just solve the problems for you, in my case, they gave me the confidence and security I had lost with those stupid professors and the way they teach. To be honest, studying the programs on my calculator taught  me how to solve problems that I couldn’t do before due to the way they were presented. I felt confident and secure yesterday, and it only possible because either I remember  how to do the problems or the calculator would. Thanks one more time for time, dedication and quick responses. There is no other person in the whole world that would do what you do for us , college students being  killed  with freaking calculus classes.      John

Tom-     Got it to work with that link you sent me!  Just wanted to say thanks for all the great work you do, and for helping me pass this calculus class.  I’m going to tell everyone about this and make them pay the $30 dollars because you have done a splendid job programming my friend.  Let me know if you have any new programs for derivatives or integrals and Ill let you know if I need any more help!  Much thanks,                –Eric

I basically just needed to say that you’re an amazing man. Basically saved my life during my emag theory course    

-DoubtingThomas  (Youtube vectors review here)

oh my god I figured it out. You’re the freaking best!      -Sarah

Thanks Tom. I appreciate you taking the time to break down and explain these to me. :0)     –Nelson

 Tommy,     Great talking with you last night. I already liked you for developing this “most excellent program” but after our conversation I concluded you to be a great guy. I’ve been playing with this program most of the night, took in a few “z’s” and am back for more. This program really is superb. I did, however, notice that for some unknown reason when I attempt to do Relative Extrema’s and Trajectories that both programs came up as “Program not Found”. I’m not sure if I will be encountering the Trajectory stuff in this semester of Calculus but I do have a test this Thursday that includes Relative Extrema. Any suggestion, oh Master of this great creation?! I’m going to be gone most the day but should be home late afternoon if you got time to call. Same number (843-xxx-xxxx). That’s Myrtle Beach, 3 hours ahead of you and more golf courses than you can shake a stick at. Thanks    -Joe

Wow! Awesome! These are great, so great, thank you!            -Kristen

Tom is the man! His program is helping me pass my calculus class. He was willing to help me immediately when I couldn’t get one of the programs working! This application is in my opinion a STEAL! I’ve never met Tom in person but I’ll owe passing this class to every step calculus.            

-YouTube product rule video comment

CALCULUS 2 & 3 PROGRAMS

A & B   Vectors A(x,y,z) B(x,y,z)  ||A|| Magnitude  ||B|| Magnitude  |  A – B  |  A – B Magnitude  |  A + B  |  A + B Magnitude  |  A + B + C  |  Find Resultant  |  Find Components  |  A * B Dot Product  |  |  A x B Cross Prod  |  B – A  |  n * A  |  (n * A) + (n * B)  |   Area of a parallelogram  |  Component A direct B  |  cosine(AB)  |  Equation of a Plane  |   ax+by+cz+d=0  |  P&Q Points  |   Projection of A on B  |  Projection of B on A  |  Unit vector A  |  Unit vector B   Video Example

Acceleration  |  r(t) function

Angle of a Vector  |  r(t) function

Arc Length  |  f(x) system  |  r(t) system  |  y system

Average Rate of Change

Component of A Direction of B

Conservative Curl

Compute Curl at a Point

Compute Divergence at a Point

Cosine(∅) of A & B

Curl | Definition  |  PQR notation  |  Conservative  |  Divergence  |  Curl Problem  |  Compute Curl at Point | Compute Divergence at Point | MNP  notation  |  Conservative  |  Divergence  |  Curl Problem  |  Compute Curl at Point | Compute Divergence at Point   Video Example

Cross Product  Video Example

Definite Integral  Video Example

Divergence of Curl

Divergence of Vector Field

Dot Product  Video Example

Eliminate the Parameter (t)

Gradient   |  Definition  |  2 Variables  |  3 Variables

Implicit Differentiation  Video Example

Trig & Half Angle Formulas  |  1 + cos(2x)2  |  1 – cos(2x)/1 + cos(2x)  |  1 – cos(2x)/2  |  cos(2x)  |  cos(x)  |  cos²(x)  |  cot(x)  |  csc(x)  |  csc²(x)  |  sec(x)  |  sec²(x)  |  sin(2x)  |  sin(x)  |  sin²(x)  |  sin²(x) + cos²(x) = 1  |  tan(x)  |  tan²(x)

Linear Equations (3 variable) | ax+by+cz+d=0

Line Integral Over Range  |  = ∫ ( f [(x(t),y(t),z(t)] * √ [ x'(t)² + y'(t)² + z'(t)² ] ) dt

Mass of Spring or Wire

Magnitude of a Vector  |  r(t) function

Parametric Equation  |  r(t) function

Partial Fractions Integration

Polar to Rectangular Conversions

Projection of Vector A on Vector B

P & Q Vector Points  | Position Vectors | Projection of a on b, b on a  |  Speed

Quadratic Formula

Sketch a Graph  | r(t) function  |  Make a Table of Points

Surface Integral  |  x,y  |  x,z  |  y,z

Position Vectors  |  Velocity  |  Acceleration  |  Speed  |  Unit Tangent Vector  |  Parametric Equation  | Standard (Linear) Equation

Speed  |  r(t) function

Sphere  |  Center Point  |  Mid Point  |  Equation  | Radius

Surface Area Revolving

Surface Integral  |  x,y  |  x,z  |  y,z

Tangent Plane to a Surface

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Calculus Cheat Sheet Video Transcript

Ok, today I’m doing a calculus cheat sheet video, many of you have asked about that,
and I’m going to do one for you here on my programs. There is no better cheat sheet
for calculus than my programs in your Titanium calculator, you load them in there. All you
want from a cheat sheet is a formula, and how to do the problem, step by step, to solve
the problem, so that you can either memorize it or learn it or help you. You’re not interested
in learning it, not interested in memorizing it, I understand. Even better in my programs,
you can add your own variables in my programs, where you can’t on a cheat sheet, so therefore
you get the actual calculations and the actual answer. A cheat sheet gives you formulas and
that’s the first thing that my programs do. When you run my programs, I give you the
formula and you write that down on your paper, the first thing to get started. And then you
go from there. So let me show you about my menu a little bit here. To get to my menu
you have to press index, put in this formula here, index eight closed parenthesis, you
do that by pressing second alpha on your calculator, and putting in these letters, I n d e x, and
then pressing alpha again and put in the eight and the closed parenthesis, and then you press
enter and then you’re into my programs. You have vectors, notice a and b vectors,
and you have x,y, and z vectors but if you only have two vectors you can put zero in
for the z variable. And you scroll down look at acceleration, arc length, chain rule, concavity,
I do graphing by hand in my programs, critical points, there’s more graphing by hand, cross
product is a vector calculation, curl for calculus three, definite integral, definition
of a derivative which is really difference quotient here. That’s the first week of
calculus very very difficult and very, very useless, dot product, all kinds of things
here, e to the x integrating, exponential functions, and uhm, implicit differentiation
that’s always good. Ah also all the way down for many, many different things, even
has something for money in here if you want to find the time value of money equations
for calculus, of course we have the quadratic equation, where you can just get the answer
by putting in your variables in your equation or I do it step by step, if you want that,
quotient rule, speed, calculations for a sphere, mid point, sphere equations, volumes for a
sphere, radius, and of course trig and half angle formulas, which are very important because
the calculators cannot enter secant or cosecant and you need to convert those to sign or cosign
to be able to do that and of course I give you the integrals and derivatives of those
trig functions, there’s no step by step its just memorization. So check out my web
site. www.EveryStepCalculus.com and now also www.EveryStepPhysics.com
don’t forget my physics programs, ah and have a good one.

 

 

Filed Under: Integrals

What Professors don't tell you about ln(x)

October 16, 2012 by Tommy

Any problem with ln(x) in it you’d choose ln(x) in my program menu

When differentiating ln(x) and when using the product rule which is necessary, where the function might be something like 5*ln(6x).  You have two functions –—— 5 and ln(6*x).  Two functions mean f(x) and g(x).

In  my programs I used in this case 5 for f(x) and ln(6*x) for g(x)

And you have the formula for product rule, h ‘ (x) = f ‘(x) * g(x) + f(x) * g ‘ (x)

Don’t worry – I do all of this for you – step by step – in my programs, however I want to mention here of again what professors don’t tell you or make you aware of, and that is

If ln(x) has a + sign or – sign in it, it makes a difference which one you use for f(x) or g(x) so for instance in a function like 5*ln(6x+1), you have to use instead of 5 for f(x) (like above) —    ln(6x+1) for f(x)

Now who told you or me about that little detail in our calculus life?

Incidentally any derivative for ln(x) has a special formula which is:

u ‘ / u

u is what’s inside of the parenthesis.

Have fun with my programs and pass calculus, never to use it again !!!

Tom

Filed Under: Integrals

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